本文介绍了如何在 JAVA 中对 JSONArray 进行排序的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
如何按对象的字段对对象的 JSONArray 进行排序?
输入:
[{ "ID": "135", "Name": "Fargo Chan" },{ "ID": "432", "Name": "Aaron Luke" },{ "ID": "252", "Name": "Dilip Singh" }];所需的输出(按名称"字段排序):
[{ "ID": "432", "Name": "Aaron Luke" },{ "ID": "252", "Name": "Dilip Singh" }{ "ID": "135", "Name": "Fargo Chan" },]; 解决方案
试试这个:
//我假设我们需要从以下字符串创建一个 JSONArray 对象String jsonArrStr = "[ { "ID": "135", "Name": "Fargo Chan" },{ "ID": "432", "Name": "Aaron Luke" },{ "ID": "252", "Name": "Dilip Singh" }]";JSONArray jsonArr = 新的 JSONArray(jsonArrStr);JSONArray sortedJsonArray = new JSONArray();列表jsonValues = new ArrayList();for (int i = 0; i < jsonArr.length(); i++) {jsonValues.add(jsonArr.getJSONObject(i));}Collections.sort( jsonValues, new Comparator() {//如果要按ID排序,可以将名称"更改为ID"私有静态最终字符串KEY_NAME =名称";@覆盖公共 int 比较(JSONObject a,JSONObject b){String valA = new String();String valB = new String();尝试 {valA = (String) a.get(KEY_NAME);valB = (String) b.get(KEY_NAME);}捕获(JSONException e){//做一点事}返回 valA.compareTo(valB);//如果要更改排序顺序,只需使用以下命令://返回-valA.compareTo(valB);}});for (int i = 0; i < jsonArr.length(); i++) {sortedJsonArray.put(jsonValues.get(i));}
排序后的 JSONArray 现在存储在 sortedJsonArray
对象中.
How to sort a JSONArray of objects by object's field?
Input:
[
{ "ID": "135", "Name": "Fargo Chan" },
{ "ID": "432", "Name": "Aaron Luke" },
{ "ID": "252", "Name": "Dilip Singh" }
];
Desired output (sorted by "Name" field):
[
{ "ID": "432", "Name": "Aaron Luke" },
{ "ID": "252", "Name": "Dilip Singh" }
{ "ID": "135", "Name": "Fargo Chan" },
];
解决方案
Try this:
//I assume that we need to create a JSONArray object from the following string
String jsonArrStr = "[ { "ID": "135", "Name": "Fargo Chan" },{ "ID": "432", "Name": "Aaron Luke" },{ "ID": "252", "Name": "Dilip Singh" }]";
JSONArray jsonArr = new JSONArray(jsonArrStr);
JSONArray sortedJsonArray = new JSONArray();
List<JSONObject> jsonValues = new ArrayList<JSONObject>();
for (int i = 0; i < jsonArr.length(); i++) {
jsonValues.add(jsonArr.getJSONObject(i));
}
Collections.sort( jsonValues, new Comparator<JSONObject>() {
//You can change "Name" with "ID" if you want to sort by ID
private static final String KEY_NAME = "Name";
@Override
public int compare(JSONObject a, JSONObject b) {
String valA = new String();
String valB = new String();
try {
valA = (String) a.get(KEY_NAME);
valB = (String) b.get(KEY_NAME);
}
catch (JSONException e) {
//do something
}
return valA.compareTo(valB);
//if you want to change the sort order, simply use the following:
//return -valA.compareTo(valB);
}
});
for (int i = 0; i < jsonArr.length(); i++) {
sortedJsonArray.put(jsonValues.get(i));
}
The sorted JSONArray is now stored in the sortedJsonArray
object.
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