Python：创建对象并向其添加属性

问题描述

我想在Python中创建一个动态对象（在另一个对象内部），然后向其中添加属性。

我试过：

  $ 
 
 
 
如何设置基于属性的属性上面的例子中 p 的价值？
解决方案
使用我古老的食谱，但如果你不想做一个束类，一个非常简单的一个已经存在于Python  - 所有函数可以有任意属性（包括lambda函数）。所以，以下工作：
  obj = someobject 
 obj.a = lambda：None 
 setattr obj.a，'somefield'，'somevalue'）
  
  Bunch 食谱是OK的，是一个风格决定我当然会留给你。
 
I want to create a dynamic object (inside another object) in Python and then add attributes to it.
I tried:
obj = someobject
obj.a = object()
setattr(obj.a, 'somefield', 'somevalue')
but this didn't work.
Any ideas?
edit:
I am setting the attributes from a for loop which loops through a list of values, e.g.
params = ['attr1', 'attr2', 'attr3']
obj = someobject
obj.a = object()

for p in params:
   obj.a.p # where p comes from for loop variable
In the above example I would get obj.a.attr1, obj.a.attr2, obj.a.attr3.  
I used the setattr function because I didn't know how to do obj.a.NAME from a for loop.
How would I set the attribute based on the value of p in the example above?
 解决方案 
You could use my ancient Bunch recipe, but if you don't want to make a "bunch class", a very simple one already exists in Python -- all functions can have arbitrary attributes (including lambda functions).  So, the following works:
obj = someobject
obj.a = lambda: None
setattr(obj.a, 'somefield', 'somevalue')
Whether the loss of clarity compared to the venerable Bunch recipe is OK, is a style decision I will of course leave up to you.
                        
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