问题描述
我的应用程序的构造如下:
My application is constructed as follows:
- 主窗口允许用户选择CSV文件进行解析
- 选择CSV文件后,JOptionPane将出现,JOptionPane包含一个带有多种选择的下拉菜单;每个都生成一个单独的窗口
- 目前,JOptionPane在从菜单中进行选择后关闭,点击确定按钮
我正在寻找一种强制JOptionPane保持打开状态的方法,以便用户可以选择不同的东西。我想要通过点击右上角的X关闭JOptionPane。如果使用JOptionPane不是最好的方式,我也可以使用其他可能性来实现类似的结果。
I am looking for a way to force the JOptionPane to remain open so that the user can select something different if they want. I would like the JOptionPane to be closed only by clicking the "X" in the upper right corner. I am also open to other possibilities to achieve a similar result if using a JOptionPane isn't the best way to go on this.
这是相关的代码块I 'm work on:
Here is the relevant block of code I'm working on:
try
{
CSVReader reader = new CSVReader(new FileReader(filePath), ',');
// Reads the complete file into list of tokens.
List<String[]> rowsAsTokens = null;
try
{
rowsAsTokens = reader.readAll();
}
catch (IOException e1)
{
e1.printStackTrace();
}
String[] menuChoices = { "option 1", "option 2", "option 3" };
String graphSelection = (String) JOptionPane.showInputDialog(null,
"Choose from the following options...", "Choose From DropDown",
JOptionPane.QUESTION_MESSAGE, null,
menuChoices, // Array of menuChoices
menuChoices[0]); // Initial choice
String menuSelection = graphSelection;
// Condition if first item in drop-down is selected
if (menuSelection == menuChoices[0] && graphSelection != null)
{
log.append("Generating graph: " + graphSelection + newline);
option1();
}
if (menuSelection == menuChoices[1] && graphSelection != null)
{
log.append("Generating graph: " + graphSelection + newline);
option2();
}
if (menuSelection == menuChoices[2] && graphSelection != null)
{
log.append("Generating graph: " + graphSelection + newline);
option3();
}
else if (graphSelection == null)
{
log.append("Cancelled." + newline);
}
}
推荐答案
这些选项窗格中的任一个,我可以在关闭之前更改我的选择多次。第三个选项窗格将显示(默认)先前在第1个 - 当前值中选择的值。
In either of these option panes, I can change my choice as many times as I like before closing it. The 3rd option pane will show (default to) the value selected earlier in the 1st - the current value.
import java.awt.*;
import javax.swing.*;
class Options {
public static void main(String[] args) {
Runnable r = new Runnable() {
@Override
public void run() {
Object[] options = {
"Option 1",
"Option 2",
"Option 3",
"None of the above"
};
JComboBox optionControl = new JComboBox(options);
optionControl.setSelectedIndex(3);
JOptionPane.showMessageDialog(null, optionControl, "Option",
JOptionPane.QUESTION_MESSAGE);
System.out.println(optionControl.getSelectedItem());
String graphSelection = (String) JOptionPane.showInputDialog(
null,
"Choose from the following options...",
"Choose From DropDown",
JOptionPane.QUESTION_MESSAGE, null,
options, // Array of menuChoices
options[3]); // Initial choice
System.out.println(graphSelection);
// show the combo with current value!
JOptionPane.showMessageDialog(null, optionControl, "Option",
JOptionPane.QUESTION_MESSAGE);
}
};
// Swing GUIs should be created and updated on the EDT
// http://docs.oracle.com/javase/tutorial/uiswing/concurrency/initial.html
SwingUtilities.invokeLater(r);
}
}
我觉得Michael猜到了一个 JList的
。以下是& 。
I think Michael guessed right with a JList
. Here is a comparison between list & combo.
请注意, JList
& JComboBox
可以使用组合中看到的渲染器。重要的区别是列表是支持多重选择的嵌入式组件。
Note that both JList
& JComboBox
can use a renderer as seen in the combo. The important difference is that a list is an embedded component that supports multiple selection.
这篇关于Force JOptionPane保持开放的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!