调度Swingworker线程

问题描述

我有两个进程在我的swing应用程序中执行，一个填充列表，一个对列表上的每个元素执行操作。我刚刚将2个进程移动到Swingworker线程来停止GUI锁定，而执行任务，并且因为我将需要对多个列表执行这组操作，因此并发性不会是一个坏主意在第一地点。但是，当我刚刚运行

I have a 2 processes to perform in my swing application, one to fill a list, and one to do operations on each element on the list. I've just moved the 2 processes into Swingworker threads to stop the GUI locking up while the tasks are performed, and because I will need to do this set of operations to several lists, so concurrency wouldn't be a bad idea in the first place. However, when I just ran

doStuffToList线程在空列表（duh ...）上运行。如何告诉第二个进程等待第一个进程完成？我想我可以在第一个进程结束时嵌套第二个进程，但是我dunno，这似乎是不好的做法。

the doStuffToList thread to ran on the empty list (duh...). How do I tell the second process to wait until the first one is done? I suppose I could just nest the second process at the end of the first one, but i dunno, it seems like bad practice.

推荐答案

p>这样的东西会吗？

Something like this would do it, I think?

boolean listIsFull=false;
class FillListWorker extends SwingWorker<Foo,Bar>
{
    ...
    protected void done()
    {
        synchronized (listYouveBeenFilling)
        {
            listIsFull=true;
            listYouveBeenFilling.notifyAll();
        }
    }
    ...
}

class DoStuffToListListWorker extends SwingWorker<Foo,Bar>
{
    ...
    protected Foo doInBackground()
    {
        synchronized (listYouveBeenFilling)
        {
            while (!listIsFull)
            {
                try
                {
                    listYouveBeenFilling.wait();
                }
                catch (InterruptedException ie)
                {
                    // Don't worry, we'll just wait again
                }
            }
        }
    }
    ...
}

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