问题描述
我看到保存原始的字符数。但是我应该如何将它转换成正常的字符串,以便在UILabel中使用文本?
提前感谢
我写了一些代码来迭代和记录所有可能的组合。
起初我在NSString.h中找到了所有可能的编码列表并将其设置为C数组可能的编码:
int encodings [] = {
NSASCIIStringEncoding,
NSNEXTSTEPStringEncoding,
NSJapaneseEUCStringEncoding,
NSUTF8StringEncoding,
NSISOLatin1StringEncoding,
NSSymbolStringEncoding,
NSNonLossyASCIIStringEncoding,
NSShiftJISStringEncoding,
NSISOLatin2StringEncoding,
NSUnicodeStringEncoding,
NSW WindowsCP1251StringEncoding,
NSWindowsCP1252StringEncoding,
NSWindowsCP1253StringEncoding,
NSWindowsCP1254StringEncoding,
NSWindowsCP1250StringEncoding,
NSISO2022JPStringEncoding,
NSMacOSRomanStringEncoding,
NSUTF16StringEncoding,
NSUTF16BigEndianStringEncoding,
NSUTF16LittleEndianStringEncoding,
NSUTF32StringEncoding,
NSUTF32BigEndianStringEncoding,
NSUTF32LittleEndianStringEncoding
};
现在让我们重复一遍并显示所有可能的结果:
int numberOfEncodings = 23; (int i = 0; i< numberOfEncodings; i ++)
{
NSLog(@===============%d == ===========,编码[i]);
constchar * asd = [value cStringUsingEncoding:encodings [i]];
if(asd == NULL){
NSLog(@asd == NULL);
} else {
for(int j = 0; j< numberOfEncodings; j ++){
NSString * str = [NSStringstringWithCString:asd encoding:encodings [j]];
NSLog(@%d:%@,编码[j],str);
}
}
}
之后,我查看结果并发现好字符串。这就是全部=)
注意:所有编码都是NSStringEncoding枚举的值。你可以认为你可以从0迭代到编码的数量,而不是定义编码[]数组。但是您不应该这样做,因为编码值不是上升的int。例如NSMacOSRomanStringEncoding = 30,其中一些编码是另一个的别名。而不是更好地定义可能编码的数组。
I got strings like this from audio stream as titles:
I know that this string in russian. And I need to show it correctly in UILabel.I try this:
NSData *data = [value dataUsingEncoding:NSNonLossyASCIIStringEncoding];
NSString *goodValue = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];
Now goodValue
contains next value:
Number of characters as I see the save with original. But how I should convert it into normal string for using as text in UILabel?
Thanks in advance.
I wrote some code for iterating and logging all possible combinations.
At first I found list of all possible encodings in NSString.h and set it to C array of possible encodings:
int encodings[] = {
NSASCIIStringEncoding,
NSNEXTSTEPStringEncoding,
NSJapaneseEUCStringEncoding,
NSUTF8StringEncoding,
NSISOLatin1StringEncoding,
NSSymbolStringEncoding,
NSNonLossyASCIIStringEncoding,
NSShiftJISStringEncoding,
NSISOLatin2StringEncoding,
NSUnicodeStringEncoding,
NSWindowsCP1251StringEncoding,
NSWindowsCP1252StringEncoding,
NSWindowsCP1253StringEncoding,
NSWindowsCP1254StringEncoding,
NSWindowsCP1250StringEncoding,
NSISO2022JPStringEncoding,
NSMacOSRomanStringEncoding,
NSUTF16StringEncoding,
NSUTF16BigEndianStringEncoding,
NSUTF16LittleEndianStringEncoding,
NSUTF32StringEncoding,
NSUTF32BigEndianStringEncoding,
NSUTF32LittleEndianStringEncoding
};
And now let's iterate and show all possible results:
int numberOfEncodings = 23;
for (int i = 0; i < numberOfEncodings; i++) {
NSLog(@"=============== %d =============", encodings[i]);
constchar *asd = [value cStringUsingEncoding:encodings[i]];
if (asd == NULL) {
NSLog(@"asd == NULL");
} else {
for (int j = 0; j < numberOfEncodings; j++) {
NSString *str = [NSStringstringWithCString:asd encoding:encodings[j]];
NSLog(@"%d: %@", encodings[j], str);
}
}
}
After that I look through results and found good string. That's all =)
note: all encodings are values of NSStringEncoding enum. And you could think that you could iterate from 0 to number of encodings instead of defining encodings[] array. But you shouldn't do this, because encoding values are not ascending ints. For example NSMacOSRomanStringEncoding = 30 and some of this encoding are aliases for another. Than better to define array of possible encodings.
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