本文介绍了如何将以下查询转换为sqlite格式(语法)。或者如何在sql lite中使用'NOT IN'的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧! 问题描述 开始 tran - rollback tran insert into nfc_DeliveryPlan(patient_id,contact_id,isactive,createddate,modifieddate,CreatedUserId) select patient_id,contact_id, 1 ,' 2013-12-05', NULL ,patient_id 来自 nfc_careplan_contacts 其中 contact_id 不 ( select contact_id 来自 nfc_DeliveryPlan 其中 contact_id = 420 ) 和 contact_id = 420 解决方案 您的查询永远不会返回任何结果!因为你的条款总是假的! 因为你不能使用join,那就更优化了! String query = 选择patient_id,contact_id,1,'2013-12-05',NULL,patient_id来自nfc_careplan_contacts左连接nfc_DeliveryPlan b on a .contact_id = b.contact_id,其中a.contact_id = 420,b.contact_id = 420,a.contact_id!= b.contact_id)和a.contact_id = 420;; 光标 c = 数据库 .rawQuery(查询,空); begin tran --rollback traninsert into nfc_DeliveryPlan (patient_id,contact_id,isactive,createddate,modifieddate,CreatedUserId)select patient_id, contact_id, 1, '2013-12-05', NULL, patient_id from nfc_careplan_contactswhere contact_id not in (select contact_id from nfc_DeliveryPlan where contact_id = 420)and contact_id = 420 解决方案 Your query never return any result! because of your terms which are always false!for not in you can use join, that's more optimize!String query = "select patient_id, contact_id, 1, '2013-12-05', NULL, patient_id from nfc_careplan_contacts a left join nfc_DeliveryPlan b on a.contact_id = b.contact_id where a.contact_id = 420 and b.contact_id = 420 and a.contact_id != b.contact_id) and a.contact_id = 420;";Cursor c = database.rawQuery(query, null); 这篇关于如何将以下查询转换为sqlite格式(语法)。或者如何在sql lite中使用'NOT IN'的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持! 10-23 04:29