如何获得子节点&使用C#动态生成父节点的子节点的值

问题描述

朋友们，

我正在尝试使用c#动态创建xml文件.我想创建xml文件，如下所示:

Hi friends,

i m trying to creat a xml file dynamically using c#.i want to create xml file like this :

<?xml version="1.0" encoding="utf-8" ?>
- <Hospitalizations>
- <Hospitalization Id="">
  <Patient_Id>REG-10010</Patient_Id>
  <FileId>REG-10010</FileId>
  <date_of_admission>29/07/2010 13:56:16</date_of_admission>
  <date_of_discharge>31/07/2010 14:55:49</date_of_discharge>
<ward Date="08/12/2011">General</ward>
  <admission_type>Genral</admission_type>
- <Wards>
  <ward Date="08/12/2011">General</ward>
  <ward Date="08/12/2011">General2</ward>
  </Wards>
  <primary_department>Obs. & Gynae</primary_department>
  <primary_doctor_name>Vandana Bansal MS,FCGP,D.Phil</primary_doctor_name>
  <discharge_type />
  <discharge_details>31/07/2010 14:55:49,</discharge_details>
- <diagnosis>
  <entry>None</entry>
  </diagnosis>
  </Hospitalization>
  </Hospitalizations>

亲切地建议我如何检索子节点&动态添加到主XML节点.

谢谢&问候
Gulam Hussain

kindly suggest me that how to retrieve child node & Add Into Main XML Node dynamically.

Thanks & Regards
Gulam Hussain

推荐答案

Hospitalizations.Descendants.Element("Hospitalization1").Add(new XElement("List of Procedures"));

如Addy Tas所建议，XPath(System.Linq.XPath)可能在此处可用于访问元素:[ ^ ].

As suggested by Addy Tas, XPath (System.Linq.XPath) may be useful here for accessing elements:[^].

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