本文介绍了Console.Read()和Console.ReadLine()问题的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我一直在尝试在C#中使用Console.Read()和Console.ReadLine(),但结果却很奇怪。例如,这段代码

I have been trying to use Console.Read() and Console.ReadLine() in C# but have been getting weird results. for example this code

Console.WriteLine("How many students would you like to enter?");
int amount = Console.Read();
Console.WriteLine("{0} {1}", "amount equals", amount);

for (int i=0; i < amount; i++)
{
     Console.WriteLine("Input the name of a student");
     String StudentName = Console.ReadLine();
     Console.WriteLine("the Students name is " + StudentName);
}

当我输入1的数字时,一直给我的金额= 49学生,我什至没有机会输入学生姓名。

has been giving me that amount = 49 when I input 1 for the number of students, and Im not even getting a chance to input a student name.

推荐答案

这是因为您读取了一个字符。
使用诸如 ReadInt32()之类的适当方法,该方法可确保从读取符号到所需类型的正确转换。

This because you read a char.Use appropriate methods like ReadInt32() that takes care of a correct conversion from the read symbol to the type you wish.

得到 49 的原因是因为它是'1'符号的字符代码,而 not 是整数表示形式。

The reason why you get 49 is because it's a char code of the '1' symbol, and not it's integer representation.

char     code
0 :      48
1 :      49
2:       50
...
9:       57

例如: ReadInt32 ()如下所示:

public static int ReadInt32(string value){
      int val = -1;
      if(!int.TryParse(value, out val))
          return -1;
      return val;
}

并像这样使用:

int val = ReadInt32(Console.ReadLine());

能够创建扩展方法<,但是很遗憾,无法在静态类型和是静态类型。

It Would be really nice to have a possibility to create an extension method, but unfortunately it's not possible to create extension method on static type and Console is a static type.

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08-23 19:45