本文介绍了在Oracle中将字符串日期转换为datetime的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
如何在oracle中将此字符串日期转换为datetime.
How can I convert this string date to datetime in oracle.
2011-07-28T23:54:14Z
使用此代码会引发错误:
Using this code throws an error:
TO_DATE('2011-07-28T23:54:14Z', 'YYYY-MM-DD HH24:MI:SS')
这怎么办?
Error report:
SQL Error: ORA-01861: literal does not match format string
01861. 00000 - "literal does not match format string"
*Cause: Literals in the input must be the same length as literals in
the format string (with the exception of leading whitespace). If the
"FX" modifier has been toggled on, the literal must match exactly,
with no extra whitespace.
*Action: Correct the format string to match the literal.
更新:-
TO_DATE('2011-07-28T23:54:14Z'，'YYYY-MM-DD"T" HH24:MI:SS"Z"')
TO_DATE('2011-07-28T23:54:14Z', 'YYYY-MM-DD"T"HH24:MI:SS"Z"')
我仅在列中看到日期而不是时间
I only see the date not time in the column
28-JUL-11
推荐答案
尝试一下:TO_DATE('2011-07-28T23:54:14Z', 'YYYY-MM-DD"T"HH24:MI:SS"Z"')
这篇关于在Oracle中将字符串日期转换为datetime的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！