匹配Linux Grep命令字符串之间的任何内容

问题描述

我已阅读，但我没有使用XML，所以它与我的Linux命令有点不同。

我有以下数据：

   使用<$ c 使用 gnu-awk  $ c $< / tag> 作为记录分隔符： 
 
 
  awk -v RS ='< ; / tag>''RT {gsub（/ \ n /，）;打印$ 0 RT}'文件
 
< tag>示例行1< / tag> 
< tag>示例行2< / tag> 
  
 
I have read the post grep all characters including newline but I not working with XML so it's a bit different with my Linux command.
I have the following data:
Example line 0</span>
<tag>Example line 1</tag>
<span>Example line 1.5</span>
<tag>
Example line 2
</tag>
Example line 3
<span>Example line 4</span>
Using this command cat file.txt | grep -o '<tag.*tag>\|^--.*' I get:
<tag>Example line 1</tag>
However, I want the output to be:
<tag>Example line 1</tag>
<tag>Example line 2</tag>
How can I match anything between the strings, including the newline? 
Note: I need to used <tag and tag> as strings because other files can contain multiple tags and text in between the lines. Will update sample data to show that. 
 解决方案 
This is easier done with gnu-awk using </tag> as record separator:
awk -v RS='</tag>' 'RT {gsub(/\n/, ""); print $0 RT}' file

<tag>Example line 1</tag>
<tag>Example line 2</tag>
                        
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