因为许多UI组件都需要此WPF

因为许多UI组件都需要此WPF

本文介绍了调用线程必须是STA,因为许多UI组件都需要此WPF的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在使用 WPF工具包提供的MessageBox.而且我得到了错误

I am using the MessageBox provided by WPF Toolkit. And I get the error

调用线程必须是STA,因为许多UI组件都需要

new Thread(new ThreadStart(delegate
{
    MessageBox.Show("Opeartion could not be completed. Please try again.","Error",MessageBoxButton.OK,MessageBoxImage.Error);
})).Start();

在这种情况下如何设置ApartmentState

How can I set the ApartmentState in this case

我正在尝试使用WPF Toolkit的MessageBox控件显示无模式的MessageBox.到目前为止,我拥有的代码如下:

I am trying to display a modeless MessageBox using MessageBox control of WPF Toolkit.So far the code I have is as follows:

void SomeFunction()
{
// calls to some UI, and processing and then

var th = new Thread(new ThreadStart(delegate
                                        {
                                           MessageBox.Show("Opeartion could not be completed. Please try again.",
                                                "Error", MessageBoxButton.OK, MessageBoxImage.Error);
                                        }));

                                        th.SetApartmentState(ApartmentState.STA);
                                        th.Start();
                                    }
}

推荐答案

// enable unit test to mock a dispatcher
var dispatcher = Dispatcher.CurrentDispatcher;
if (Application.Current != null)
{
    // use the application dispatcher if running from the software
    dispatcher = Application.Current.Dispatcher;
}

if (dispatcher != null)
{
    // delegate the operation to UI thread.
    dispatcher.Invoke(
        delegate
        {
            MessageBox.Show("Opeartion could not be completed. Please try again.","Error",MessageBoxButton.OK,MessageBoxImage.Error);
        });
}

这篇关于调用线程必须是STA,因为许多UI组件都需要此WPF的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

08-23 17:35