处理-通过按“1"键或“2"键来选择形状，以便分别拾取形状 1 或形状 2

问题描述

在草图上绘制两个形状(例如矩形和圆形).使用 UP、DOWN、LEFT 和 RIGHT 键控制所选形状的移动.通过按1"键或2"键选择形状，以便分别选择形状 1 或形状 2.我想通过按1"键选择形状或2"，但它们无法运行.`

Draw two shapes on the sketch (e.g. a rectangle and a circle). Use the UP, DOWN, LEFT and RIGHT keys to control the movement of the selected shape. A shape is selected by either pressing a key ‘1’ or or key ‘2’ so that shape 1 or shape 2 can be picked up respectively.I want to select the shape by pressing the key "1" or "2", but they cannot run.`

int x = 0;
int y = 0;
int ex= 0;
int ey= 0;

void setup(){
  size (400, 400);
}

void draw(){
  background(80);
  rect(x, y, 25,25);
  ellipse(50, 50, 50, 50);
}

void keyPresse() {
  if ( (key == '1')) {
    if (keyCode == UP) {
      y -= 10;
    } else if (keyCode == DOWN) {
      y += 10;
    } else if (keyCode == LEFT) {
      x -= 10;
    } else if (keyCode == RIGHT) {
      x += 10;
    }
  } else if ((key == '2')){
      if (keyCode == UP) {
      ey -= 10;
    } else if (keyCode == DOWN) {
      ey += 10;
    } else if (keyCode == LEFT) {
      ex -= 10;
    } else if (keyCode == RIGHT) {
      ex += 10;
    }
  }
}

推荐答案

有一个错字.键盘回调的名称是 keyPressed.但是，也存在一些逻辑问题.

There is a typo. The name of the key board callback is keyPressed. However, there are also some logical issues.

为 x 和 y 坐标创建一个数组.还有一个索引变量 (shape_i):

Crate an array for the x and y coordinates. And an index variabel (shape_i):

int x[] = new int[]{100, 100};
int y[] = new int[]{200, 100};
int shape_i = 0;

在其位置绘制形状.(x[0], y[0]) 是矩形的位置，(x[1], y[1]) 是椭圆的位置:

Draw the shapes on its position. (x[0], y[0]) is the position of the rectangle and (x[1], y[1]) is the position of the ellipse:

void draw(){
  background(80);
  rect(x[0], y[0], 25, 25);
  ellipse(x[1], y[1], 50, 50);
}

当按下 或 时更改索引 (shape_i).按下箭头键时更改 (x[shape_i], y[shape_i]):

Change the index (shape_i) when or is pressed. Change (x[shape_i], y[shape_i]) when an arrow key is pressed:

void keyPressed() {
  if (key == '1') {
    shape_i = 0;
  } else if (key == '2') {
    shape_i = 1;
  } else if (keyCode == UP) {
    y[shape_i] -= 10;
  } else if (keyCode == DOWN) {
    y[shape_i] += 10;
  } else if (keyCode == LEFT) {
    x[shape_i] -= 10;
  } else if (keyCode == RIGHT) {
    x[shape_i] += 10;
  }
}

---

完整示例:

---

Complete example:

int x[] = new int[]{100, 100};
int y[] = new int[]{200, 100};
int shape_i = 0;

void setup(){
  size (400, 400);
}

void draw(){
  background(80);
  rect(x[0], y[0], 25, 25);
  ellipse(x[1], y[1], 50, 50);
}

void keyPressed() {
  if (key == '1') {
    shape_i = 0;
  } else if (key == '2') {
    shape_i = 1;
  } else if (keyCode == UP) {
    y[shape_i] -= 10;
  } else if (keyCode == DOWN) {
    y[shape_i] += 10;
  } else if (keyCode == LEFT) {
    x[shape_i] -= 10;
  } else if (keyCode == RIGHT) {
    x[shape_i] += 10;
  }
}

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