循环中重复的随机数

问题描述

对于每个不同的循环，需要在0和1之间建立一个随机数。

为（1到10000）调用RandomKey函数，以便生成不同的随机数。
但是问题是每次迭代都得到相同的数字。

RandomKey函数如下：

  void RandomKey b $ b {
 srand（（unsigned）time（0））; 
 for（int k = 0; k  {
 
 Act_num [k] .Priority =（rand（）％10000）* 0.0001; // random数字
 
} 
 
 
 for（int i = 0; i  arr [i] = Act_num [i] ; 
  

我如何解决这个问题？

至少有三件事你应该验证：

• 在您的计划中只拨打 srand 一次
  
• 如果 srand 被多次调用，或者您的程序每秒运行多次，则。


• 如果每个随机数只应为0或1，你应该调用（int）（rand（）& 1）得到从零到一个均匀分布的数字。如果您需要在0.0和1.0之间的浮动，则需要以不同的方式。

：如果您只想要一个在零和一之间的随机浮点数，请参阅

A need to generatera random numbers between 0 and 1 for every different loop.

for ( 1 to 10000) a call RandomKey function so as to generate different random numbers.But the problem is every iteration i get same numbers.

RandomKey function is as follows:

 void RandomKey ()
 {
   srand((unsigned)time(0));
   for (int k=0;k<ActivityNumber;k++)
 {

Act_num[k].Priority=(rand()%10000)*0.0001;//random number

 }


for (int i=0;i<ActivityNumber;i++)
   arr[i]=Act_num[i].Priority;

How can i solve the problem?

解决方案

(I'm restating the other suggestions here.)

There are at least three things you should verify:

• Only call srand once in your program
• If srand is called more than once, or your program is run many times per second, then do not use time(0) to initialize srand.
• If each random number should only be 0 or 1, you should call (int)(rand() & 1) to get uniformly distributed numbers from zero to one. If you need floats between 0.0 and 1.0, you need to do it differently.

EDIT: If you just want a random floating point number between zero and one, see Generating random number between [-1, 1] in C?

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