- Frederick GothamHow do we initialise an aggregate member object of a class? The followingwon''t compile for me:struct MyStruct {int i;double d;};class MyClass {private:MyStruct const obj;public:MyClass() : obj( {5,45.67} ) {}};int main(){MyClass obj;}--Frederick Gotham推荐答案 Frederick Gotham写道:Frederick Gotham wrote: 我们如何初始化类的聚合成员对象?以下 不会为我编译:How do we initialise an aggregate member object of a class? The followingwon''t compile for me: struct MyStruct { int我; 加倍;struct MyStruct { int i; double d; 给编译器一些帮助: MyStruct(int ii,double dd):i(ii),d (dd){}Give the compiler a little help:MyStruct(int ii, double dd) : i(ii), d(dd) {} }; class MyClass { private: MyStruct const obj; public: MyClass():obj({5,45.67}){}};class MyClass {private: MyStruct const obj;public: MyClass() : obj( {5,45.67} ) {} 切换到: MyClass():obj(MyStuct(5,45.67)){}switch it to:MyClass() : obj(MyStuct(5, 45.67)) {} }; int main() { MyClass obj; }};int main(){ MyClass obj;} 并且不用担心构造的额外MyStruct和 复制 - 你的编译器应该优化那个 - 或者 否则切换到更好的编译器。 祝你好运, TomAnd don''t worry about the extra MyStruct that gets constructed andcopied - your compiler ought to optimize that right out of there - orelse switch to a better compiler.Best regards,Tom Thomas Tutone< Th *********** @ yahoo.comwrote:Thomas Tutone <Th***********@yahoo.comwrote: 弗雷德ick Gotham写道:Frederick Gotham wrote: >我们如何初始化类的聚合成员对象?以下不会为我编译:>How do we initialise an aggregate member object of a class? The followingwon''t compile for me: > struct MyStruct { int i; 双d;>struct MyStruct { int i; double d; 给编译器一些帮助: MyStruct(int ii,double dd):i(ii),d (dd){}Give the compiler a little help: MyStruct(int ii, double dd) : i(ii), d(dd) {} >}; 类MyClass {私人: MyStruct const obj; 公开: MyClass():obj({5,45.67}){}>};class MyClass {private: MyStruct const obj;public: MyClass() : obj( {5,45.67} ) {} 切换到: MyClass():obj(MyStuct(5,45.67)){}switch it to: MyClass() : obj(MyStuct(5, 45.67)) {} 即使这不是必要的;你可以拥有: MyClass():obj(5,45.67){}Even that is not necessary; you can just have:MyClass() : obj(5, 45.67) { } >}; int main() { MyClass obj; }>};int main(){ MyClass obj;} 并且不要担心构造的额外MyStruct和 复制 - 你的编译器应该优化那个 - 或者 否则切换到更好的编译器And don''t worry about the extra MyStruct that gets constructed andcopied - your compiler ought to optimize that right out of there - orelse switch to a better compiler. - Marcus Kwok 将''invalid''替换为''net''来回复--Marcus KwokReplace ''invalid'' with ''net'' to reply struct MyStruct {struct MyStruct { int i; 双d; int i; double d; 给编译器一些帮助: MyStruct(int ii,double dd):i(ii),d (dd){}Give the compiler a little help: MyStruct(int ii, double dd) : i(ii), d(dd) {} }; class MyClass { private: MyStruct const obj; public: MyClass():obj({5,45.67}){} }; class MyClass { private: MyStruct const obj; public: MyClass() : obj( {5,45.67} ) {} 切换到: MyClass():obj(MyStuct(5,45.67)){}switch it to: MyClass() : obj(MyStuct(5, 45.67)) {} }; int main() { MyClass obj; } }; int main() { MyClass obj; } 并且不用担心构造的额外MyStruct和 复制 - 你的编译器应该优化那个And don''t worry about the extra MyStruct that gets constructed andcopied - your compiler ought to optimize that right out of there 为什么要复制它? MyClass():obj(5,45.67) {}why copy it at all?MyClass () : obj (5, 45.67) {} 这篇关于如何初始化聚合成员?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持! 上岸,阿里云! 08-23 15:58