本文介绍了如何在JavaScript中随机播放对象数组?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
下面的代码适用于普通数组,但不适用于带有对象的数组吗?有人知道如何执行此操作吗?
The code below works for a normal array but not with an array with object does anybody knows how to do this?
const array = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10];
function shuffle(array) {
for (let i = array.length - 1; i > 0; i--) {
let j = Math.floor(Math.random() * (i + 1));
let temp = array[i];
array[i] = array[j];
array[j] = temp;
}
return array;
}
const result = shuffle(array);
console.log(JSON.stringify(result));
推荐答案
尝试按以下代码段进行排序:
Try sorting like this snippet:
console.log( [
{ some: 1 },
{ some: 2 },
{ some: 3 },
{ some: 4 },
{ some: 5 },
{ some: 6 },
{ some: 7 },
]
.sort( () => Math.random() - 0.5) );
回应Martin Omanders评论:这是根据 Fisher-耶茨算法
In reponse to Martin Omanders comment: here's a shuffle method according to the Fisher-Yates algorithm
for (let i=0; i<20; i+=1) {
console.log(JSON.stringify(shuffleFisherYates([0,1,2,3,4,5,6,7,8,9])));
}
function shuffleFisherYates(array) {
let i = array.length;
while (i--) {
const ri = Math.floor(Math.random() * (i + 1));
[array[i], array[ri]] = [array[ri], array[i]];
}
return array;
}
可能会压缩到一个衬里(注释:该衬里不会在高级级别的Google Closure编译器):
Which may be condensed to a one liner (note: this one liner will not compile in the Google Closure Compiler with level advanced):
const shuffle = array =>
[...Array(array.length)]
.map((...args) => Math.floor(Math.random() * (args[1] + 1)))
.reduce( (a, rv, i) => ([a[i], a[rv]] = [a[rv], a[i]]) && a, array);
for (let i=0; i<100; i+=1)
console.log(JSON.stringify(shuffle([0,1,2,3,4,5,6,7,8,9])));
这篇关于如何在JavaScript中随机播放对象数组?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!