c＃中离散分布随机数的标准函数

问题描述

大家好。我有个问题。在c ++ 11中有一个用于离散分布随机数的标准函数discrete_distribution



例如：

Hello all. I have a question. In c++ 11 have a standard function discrete_distribution for Discretely Distributed Random Numbers

Example:

#include <iostream>
#include <random>

int main()
{
  const int nrolls = 10000; // number of experiments
  const int nstars = 100;   // maximum number of stars to distribute

  std::default_random_engine generator;
  std::discrete_distribution<int> distribution {2,2,1,1,2,2,1,1,2,2};

  int p[10]={};

  for (int i=0; i<nrolls; ++i) {
    int number = distribution(generator);
    ++p[number];
  }

  std::cout << "a discrete_distribution:" << std::endl;
  for (int i=0; i<10; ++i)
    std::cout << i << ": " << std::string(p[i]*nstars/nrolls,'*') << std::endl;

  return 0;

}

结果：

Result:

a discrete_distribution:
0: ************
1: *************
2: *****
3: ******
4: ************
5: ************
6: ******
7: ******
8: ************
9: ************

在c＃中有标准函数，如c ++中的discrete_distribution ???谢谢大家！

In c# have standard function like discrete_distribution in c++ ??? Thanks all!

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