如何将WPF ScrollViewer的内容滚动到特定位置

问题描述

我正在编写自定义WPF ItemsControl以显示项目列表.这些项目显示为嵌入ScrollViewer内:

I am writing my custom WPF ItemsControl to display a list of item. The items are shown embedded inside a ScrollViewer:

<Style TargetType="MyCustomItemsControl">
        <Setter Property="Template">
            <Setter.Value>
                <ControlTemplate TargetType="MyCustomItemsControl">
                    <ScrollViewer x:Name="PART_MyScrollViewer" >
                           <ItemsPresenter/>
                    </ScrollViewer>
                </ControlTemplate>
            </Setter.Value>
        </Setter>
</Style>

我想确保当我将鼠标移到控件中时，特定项目(标记为选中)将滚动到鼠标位置.在我的OnMouseEnter方法中，我可以找到该项目，但是我不知道下一步该怎么做.有人知道吗?

I want to make sure that when I move the mouse into the control, a particular item (marked as selected) will be scrolled into the mouse position. In my OnMouseEnter method I am able to find the item but I don't know what to do next. Does anyone have any idea?

protected override void OnMouseEnter(MouseEventArgs e)
{
    for (int i = 0; i < Items.Count; i++)
    {
        ContentPresenter uiElement = (ContentPresenter)ItemContainerGenerator.ContainerFromIndex(i);
        var item = uiElement.Content as MyCustomObject;
        if (item.IsSelected)
        {
            // How to scroll the uiElement to the mouse position?
            break;
        }
    }
}

推荐答案

类似以下内容:

var sv = (ScrollViewer)Template.FindName("PART_MyScrollViewer", this); // If you do not already have a reference to it somewhere.
var ip = (ItemsPresenter)sv.Content;
var point = item.TranslatePoint(new Point() - (Vector)e.GetPosition(sv), ip);
sv.ScrollToVerticalOffset(point.Y + (item.ActualHeight / 2));

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