问题描述
所以我知道要绘制bezier曲线你使用:
So i know that to draw bezier curve you use:
path.setAttributeNS(null, "d", "M5,5 C5,45 45,45 45,5"):
但我想画它们在循环(不是动画)并且每次都改变它们的位置,它每次都是相同的曲线,但具有不同的开始和结束位置。而且我不知道如何在循环中更改这些属性。
but i would like to draw them in loop (not animation) and change their location every time, it will be same curve every time but with difrent start and end location. And i dont know how to change those attributes in loop.
从下面的回答中我尝试了我的代码,但它不起作用。我知道我做错了什么,但我不知道是什么。以下是modyfication后的代码:
From answer from bellow i tryd in my code but it dont work. I know i did something wrong but i dont know what. Here is my code after modyfication:
for (var i = 0; i < 100; i++) {
var x1 = 10;
var x2 = 15;
var x3 = 20;
var x4 = 30;
var x5 = 40;
var x6 = 50;
var x7 = 60;
var x8 = 70;
var attr = "M" + x1 + "," + x2 + " " + "C" + x3 + "," + x4 + " " + x5 "," + x6 + " " + x7 + "," + x8;
var path = document.createElementNS(svgns, 'path');
path.setAttributeNS("d", attr);
path.setAttributeNS(null, "fill", "none");
path.setAttributeNS(null, 'stroke', '#'+Math.round(0xffffff * Math.random()).toString(16));
document.getElementById('svgOne').appendChild(path);
}
x`s只是为了测试它是否有效,所以我犯了错误???
x`s are just to test if it works, so where i have made mistake???
推荐答案
你可以重新构造字符串:
You could recontruct the string:
var x1 = 5;
var x2 = 5;
var attr = "M" + x1 + "," + x2 + " C" + ...
path.setAttribute("d", attr);
或者使用因此,如果您已经有一条贝塞尔曲线
Or alternatively use the SVG DOM so if you already have a single bezier curve
var move = path.pathSegList.getItem(0);
var curve = path.pathSegList.getItem(1);
然后你可以使用界面设置曲线属性,例如
then you can use the SVGPathSegCurvetoCubicAbs interface to set the curve attributes e.g.
curve.x = 5;
curve.y = 10;
curve.x1 = 20
curve.y1 = 15;
curve.x2 = 12;
curve.y2= 13;
在您的尝试中
var attr = "M" + x1 + "," + x2 + " " + "C" + x3 + "," + x4 + " " + x5 "," + x6 + " " + x7 + "," + x8;
^ missing + sign
和
path.setAttributeNS("d", attr);
setAttributeNS需要3个参数,或者setAttribute需要2个。
setAttributeNS takes 3 arguments or alternatively setAttribute takes 2.
path.setAttributeNS(null, 'stroke', '#'+Math.round(0xffffff * Math.random()).toString(16));
这并不总是产生有效的笔画语法,虽然偶尔会这样做,你会看到一些输出。
this does not always produce valid stroke syntax although occasionally it does so you will see some output some times.
浏览器会在错误/网络控制台中报告这些问题,所以你真的应该尝试利用它。
browsers will report these issues in their error/web consoles so you really should try to take advantage of that.
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