本文介绍了如何从 SDL_Surface 获取特定像素的颜色?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在尝试从 SDL_Surface 获取像素的 RGB/RGBA 颜色.我在互联网上找到了这段代码,但它返回奇怪的数字(67372036 表示像素为 0 红色、0 绿色、255 蓝色)
I'm trying to get the RGB/RGBA color of pixels from a SDL_Surface. I've found this code on the internet but it returns strange numbers (67372036 for a pixel that is 0 red, 0 green, 255 blue)
Uint32 get_pixel32(SDL_Surface *surface, int x, int y)
{
Uint32 *pixels = (Uint32 *)surface->pixels;
return pixels[(y * surface->w) + x];
}
这是我一直在使用的代码:
This it the code I've been using:
Uint32 data = get_pixel32(gSurface, 0, 0);
printf("%i", data);
我不确定我的像素是否具有 32 位格式,但其他图片效果不佳.
I'm not sure if my pixels have a 32bit format but other pictures didn't work as well.
推荐答案
找到了这段代码,它运行良好.
Found this code and it's working fine.
Uint32 getpixel(SDL_Surface *surface, int x, int y)
{
int bpp = surface->format->BytesPerPixel;
/* Here p is the address to the pixel we want to retrieve */
Uint8 *p = (Uint8 *)surface->pixels + y * surface->pitch + x * bpp;
switch (bpp)
{
case 1:
return *p;
break;
case 2:
return *(Uint16 *)p;
break;
case 3:
if (SDL_BYTEORDER == SDL_BIG_ENDIAN)
return p[0] << 16 | p[1] << 8 | p[2];
else
return p[0] | p[1] << 8 | p[2] << 16;
break;
case 4:
return *(Uint32 *)p;
break;
default:
return 0; /* shouldn't happen, but avoids warnings */
}
}
SDL_Color rgb;
Uint32 data = getpixel(gSurface, 200, 200);
SDL_GetRGB(data, gSurface->format, &rgb.r, &rgb.g, &rgb.b);
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