如何用php打印$

问题描述

基本上，我有一个html块，我想在页面上回显，并且html中有$符号，而php认为这是一个变量，因此$ 1被视为变量而不是值，因此不会显示。

Basically I have a block of html that I want to echo to the page and the html has the $ sign in it and the php thinks it is a variable so $1 is treated as the variable not the value and is not displayed.

这里有标准答案，但没有用：

There is the standard answers here but none are working: PHP: How to get $ to print using echo

我的下一个想法是将字符串拆分为$并回声每个部分。

My next idea is to split the string at the $ and echo each part out.

这是我尝试回显和打印的代码。

Here is the code I have tried echo and print.

foreach ($rows as $rowmk) {
    $s = $rowmk->longdescription;
    //$s = str_replace('$', '@', $s);
    $s = str_replace('$', '\$', $s);
    //echo  "$s" . "<br>";
    print $s;
}

感谢所有帮助。

好的，我通过使用$的字符代码值来解决

OK I solved by using the character code value for $

foreach ($rows as $rowmk) {
    $s = $rowmk->longdescription;
    $s = str_replace('$', '$', $s);
    echo  $s . "<br>";
}

我认为我还是应该将其发布。

I figured I should just post it anyway.

谢谢

垫子

推荐答案

您在错误的位置进行操作。当声明双引号字符串文字（在您的情况下存储在 $ rowmk-> longdescription 中）时，便完成变量插值。完成后，您将无法执行任何操作来恢复您的 $ 。

You're doing it in the wrong place. Variable interpolating is done when double quoted string literal (which in your case is stored within $rowmk->longdescription is daclared. Once it's done, you can't really do anything to get your $s back.

解决方案，在声明字符串时进行适当的转义。

Solution, do proper escaping, when you declare the string.

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