使用 execv(C 语言)从 linux 命令提示符运行命令

问题描述

到目前为止，我唯一感到困惑的部分是如何将 execv 设置为第一个参数作为当前工作目录.我试过两个."和~"，两者都没有在屏幕上执行任何操作；/"也是一样和/~".我对如何让 execv 运行这样的东西感到困惑:

The only part I am confused on thus far is how to set up execv with the first parameter as the current working directory. I've tried both "." and "~", neither are executing anything to the screen; same for "/." and "/~". I'm confused on how to have execv run something like this:

$ ./prog ls -t -al

并让它在当前目录或与文件所在的目录相同的目录中执行程序执行后的命令(这些命令存储在argv中).

And have it execute the commands after the program execution (which are stored into argv) in the current directory, or the same directory as the file is in (which will vary based on who is using it.)

我的代码:

#include <stdlib.h>
#include <stdio.h>
#include <unistd.h>
#include <sys/types.h>

void main(int argc, char *argv[])
{
    int pid;
    int count = 0;
    char *argv2[argc+1];

    for(count = 0; count < argc-1; count++){
        argv2[count] = argv[count+1];
        printf("Argv2: %s\n", argv2[count]);  //just double checking
        argv2[argc-1] = NULL;
    }

    pid = fork();
    if(pid == 0){
        printf("Child's PID is %d. Parent's PID is %d\n", (int)getpid, (int)getppid());
        execv(".", argv2);       //<---- confused here
    }
    else{
        wait(pid);
        exit(0);
    }
}

一些示例输出:

$ ./prog ls -t -al
Argv2: ls
Argv2: -t
Argv2: -al
Child's PID is 19194. Parent's PID is 19193

推荐答案

我想 execv 是必须使用的.execvp 更好，因为它会在您的 PATH 设置中查找命令.

I guess execv is what is required to be used. execvp is a lot nicer since it will look for commands in your PATH setting.

execv(".", argv2);       //<---- confused here

...

#include <errno.h>
#include <string.h>
if ( execv(argv2[0],argv2) )
{
    printf("execv failed with error %d %s\n",errno,strerror(errno));
    return 254;
}

wait(pid);

...

pid_t wait_status = wait(&pid);

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