问题描述
我正在编写一个创建两个线程的程序.每个线程负责读取一个文本文件,每行一个字符.
I'm writing a program that creates two threads. Each thread is responsible for reading through one text file, with one char on each line.
第一个格式如下:
h
0
h
0
...
第二个格式如下:
0
i
0
i
0
i
有时可以有多个字母一个接一个,或者多个零一个接一个.但是,可以肯定的是,如果一个文件的一行有一个字母,那么第二个文件的对应行就会有一个0,反之亦然.
Sometimes there can be multiple letters after each other, or multiple zeros after each other. However, the one certainty is that if there is a letter on one line of one file, the corresponding line of the second file will have a 0, and vice versa.
线程应该继续读取文件输入到全局字符数组中,直到它们达到零.此时,它们允许另一个线程接管.并且它们不断来回,直到两个文件都被完全读取.
The threads are supposed to keep reading the file input into a global char array until they reach a zero. At this point, they allow the other thread to take over. And they keep going back and forth until both files are completely read.
此时,当我跑步时,我会得到以下变化:(1) 多个 h 后跟多个 i 或 (2)(正确答案)连续的 hihihi 流,或(3) 有时很多 i 后面跟着很多 h.所以,我知道我的同步方法已关闭.
At this point, when I run, I get variations of either (1) many h's followed by many i's or (2) (the correct answer) a continuous stream of hihihi's, or (3) sometimes many i's followed by many h's. So, I know that my synchronization methods are off.
这是我的一个线程的示例:(注意两个线程完全一样,除了打开的文件.)
Here is an example of one of my threads:(Note both threads are exactly the same, except for the file being opened.)
void *getMessage1()
{
FILE *studentOne = fopen("Student1", "r");
size_t howManyChars;
char *placeHolderChars;
int count = 1;
while (count < 501)
{
placeHolderChars = NULL;
getline(&placeHolderChars, &howManyChars, studentOne);
if(strcmp(placeHolderChars, "0\n") == 0) //if we've reached a zero
{
pthread_mutex_unlock(&lock);
}
else
{ while(1)
{
if(pthread_mutex_trylock(&lock) == 0)
{
break;
}
}
if(strlen(placeHolderChars)>0)
{
placeHolderChars[1] = '\0';
}
strcat(message,placeHolderChars);
}
free(placeHolderChars);
if(feof(studentOne))
{
pthread_mutex_unlock(&lock); //unlock
fclose(studentOne);
break;
}
count++;
}
return 0;
}
这是我的主要方法:
int main(void)
{
pthread_t id1;
pthread_t id2;
pthread_create((&id1), NULL, getMessage1, NULL);
pthread_create((&id2), NULL, getMessage2, NULL);
pthread_join(id1, NULL);
pthread_join(id2, NULL);
int j;
for (j = 0; j < 1001; j++)
{
printf ("%c ",message[j]);
}
return 0;
}
我希望得到有关如何更好地使用锁定、解锁、等待和/或信号来创建具有一致结果的工作同步技术的任何指导.
推荐答案
这里是对可以执行您想要的程序的一次尝试.测试不充分,但 ;)
Here is one attempt at a program that does what you want. Insufficiently tested, though ;)
#include <iostream>
#include <fstream>
#include <string>
#include <cassert>
#include <pthread.h>
using std::cout;
using std::ifstream;
using std::string;
const string FILE1("file1.txt");
const string FILE2("file2.txt");
enum State
{
UNINITIALIZED,
THREAD_ONE_READS,
THREAD_TWO_READS
};
struct ThreadInfo
{
State state;
string filename;
};
State state = UNINITIALIZED;
pthread_mutex_t mut = PTHREAD_MUTEX_INITIALIZER;
pthread_cond_t cond = PTHREAD_COND_INITIALIZER;
void* thread_func(void* arg)
{
// Open file 'h'.
ThreadInfo ti = *reinterpret_cast<ThreadInfo*>(arg);
ifstream infile;
infile.open (ti.filename.c_str(), std::ifstream::in);
// while (not EOF)
// Read 'h' or 'i': until 0 reached. Wake up other thread.
string line;
getline(infile, line);
while (infile.good())
{
cout << "Thread " << pthread_self() << " read " << line << '\n';
pthread_mutex_lock(&mut);
while (state == ti.state)
{
pthread_cond_wait(&cond, &mut);
}
pthread_mutex_unlock(&mut);
assert(line.length() == 1);
if (line[0] == '0')
{
pthread_mutex_lock(&mut);
state = ti.state;
cout << "Got 0, transferring, setting state to " << state << '\n';
pthread_cond_signal(&cond);
pthread_mutex_unlock(&mut);
}
else
{
cout << "Read char: " << line << '\n';
}
getline(infile, line);
}
pthread_mutex_lock(&mut);
state = ti.state;
cout << "Finishing thread, transferring, setting state to " << state << '\n';
pthread_cond_signal(&cond);
pthread_mutex_unlock(&mut);
}
int main()
{
// Create thread 1
// Create thread 2
pthread_t thread_one_handle;
pthread_t thread_two_handle;
state = THREAD_ONE_READS;
int result;
ThreadInfo info1 = { THREAD_TWO_READS, FILE1 };
result = pthread_create(&thread_one_handle, NULL, thread_func, &info1);
assert(result == 0);
ThreadInfo info2 = { THREAD_ONE_READS, FILE2 };
result = pthread_create(&thread_two_handle, NULL, thread_func, &info2);
assert(result == 0);
result = pthread_join(thread_one_handle, NULL);
assert(result == 0);
result = pthread_join(thread_two_handle, NULL);
assert(result == 0);
cout << "main(): joined both worker threads, ending program.\n";
return 0;
}
这篇关于线程同步:Back &两个文本文件的四读的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!