问题描述
我正在编写一个 C# 应用程序,它使用互操作服务访问本机 C++ DLL 中的函数.我已经在使用大约 10 个不同的功能了.
I am writing a C# application which uses Interop services to access functions in a native C++ DLL. I am already using about 10 different functions which are working.
现在我不确定如何处理将回调作为参数传递以便 DLL 可以调用我的代码.
Now I am not sure how to handle passing a callback as a parameter so that the DLL can call my code.
这里是DLL的函数原型:
Here is the function prototype of the DLL:
typedef void (WINAPI * lpfnFunc)(const char *arg1, const char *arg2)
以及允许我传递上述类型的函数:
And the function that allows me to pass the above type:
int WINAPI SetFunc(lpfnFunc f)
这是我的委托和函数定义的 C# 代码:
Here is my C# code for the delegate and function definitions:
public delegate void Func(string arg1, string arg2);
public static void MyFunc(string arg1, string arg2)
这是我的 SetFunc Interop 函数的 C# 代码:
Here is my C# code for the SetFunc Interop function:
[DllImport("lib.dll", CharSet = CharSet.Ansi)]
public static extern int SetFunc(Func lpfn);
最后是我调用 SetFunc 函数并将其传递给我的回调的代码:
And finally here is the code where I call the SetFunc function and pass it my callback:
SetFunc(new Func(MyFunc));
不幸的是,我的函数没有在应该调用的时候被调用.SetFunc 函数的返回值返回的是 Success 的错误代码,所以它要么没有调用我的函数,要么因为我的代码错误而无法工作.
Unfortunately my function is not being called when it should be. The return value of the SetFunc function is returning the error code for a Success, so either it's not calling my function or it's not working because my code is wrong.
推荐答案
这对我有用:
Calc.h(Calc.dll,C++):
Calc.h (Calc.dll, C++):
extern "C" __declspec(dllexport) double Calc(double x, double y, double __stdcall p(double, double));
Calc.cpp(Calc.dll,C++):
Calc.cpp (Calc.dll, C++):
#include "calc.h"
__declspec(dllimport) double Calc(double x, double y, double __stdcall p(double, double))
{
double s = p(x*x, y*y);
return x * y + s;
}
Program.cs(Sample.exe,C#):
Program.cs (Sample.exe, C#):
class Program
{
delegate double MyCallback(double x, double y);
[DllImport("Calc.dll", CallingConvention = CallingConvention.Cdecl)]
static extern double Calc(double x, double y, [MarshalAs(UnmanagedType.FunctionPtr)]MyCallback func);
static void Main(string[] args)
{
double z = Calc(1, 2, (x, y) => 45);
}
}
这篇关于通过 Interop/pinvoke 传递 C# 回调函数的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!