问题描述
在C ++ 11中，当我们想将值（破坏性地复制）移动到容器中时，可以使用 std :: move 来提高效率。
In C++11, we can get an efficiency boost by using std::move when we want to move (destructively copy) values into a container:
SomeExpensiveType x = /* ... */;
vec.push_back(std::move(x));
但是我找不到其他方法。我的意思是这样的：
But I can't find anything going the other way. What I mean is something like this:
SomeExpensiveType x = vec.back(); // copy!
vec.pop_back(); // argh
这在适配器上更常见（复制弹出），例如堆栈。可能存在这样的情况：
This is more frequent (the copy-pop) on adapter's like stack. Could something like this exist:
SomeExpensiveType x = vec.move_back(); // move and pop
要避免复制？这已经存在吗？我在n3000中找不到类似的内容。
To avoid a copy? And does this already exist? I couldn't find anything like that in n3000.
我有种感觉，我很想念一些显而易见的东西（例如它的不必要），所以我为 ru dum做好了准备。 ：3
I have a feeling I'm missing something painfully obvious (like the needlessness of it), so I am prepared for "ru dum". :3
推荐答案
在这里我可能完全错了，但不是您想要的
I might be total wrong here, but isn't what you want just
SomeExpensiveType x = std::move( vec.back() ); vec.pop_back();
假设SomeExpensiveType具有移动构造函数。 （当然，对于您的情况也是如此）
Assuming SomeExpensiveType has a move constructor. (and obviously true for your case)
这篇关于C ++“移出”容器的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！