CSS同样的风格为a

CSS同样的风格为a

本文介绍了CSS同样的风格为a:链接a:访问a:hover a:active,真的要写出来4次的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

Ho ho,

使用CSS时。如果CSS样式是相同的a:链接a:visited a:hover a:active确实需要写出来的次数。使用自定义链接。

When working with CSS. If the CSS style is the same for a:link a:visited a:hover a:active does one really have to write it out for times. Working with a custom link.

.DT_compare a:link {
    font-family:"Lucida Grande", Arial, sans-serif;
    font-size:11px;
    line-height:14px;
    font-weight:normal;
    font-style:normal;
    color:#EEE;
    text-align:center;
}

任何快捷方式?

Marvelous

Marvellous

推荐答案

只要忘记伪类,只选择 a

Just forget the pseudo-classes, and select only a:

.DT_compare a {
    font-family:"Lucida Grande", Arial, sans-serif;
    font-size:11px;
    line-height:14px;
    font-weight:normal;
    font-style:normal;
    color:#EEE;
    text-align:center;
}

这不是一个非常具体的选择器;如果必要,你可以找到一些其他方式来增加它,所以它推翻你的 a:hover a:active 或使用

This isn't a very specific selector though; if necessary you can find some other way to increase it so it overrules your a:hover and a:active selectors, or go with whoughton's answer instead and just specify all four of them.

再次,如果你的主要超链接样式适用于 a :hover a:active 之前没有任何东西,只要将 .DT_compare a 规则下面它应该工作正常。

Then again, if your main hyperlink styles apply to a:hover and a:active without anything before them, as long as you place your .DT_compare a rule beneath them it should work fine.

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