wait_until块给出超时错误 | until块给出超时错误

本文介绍了wait_until块给出超时错误的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

这是我失败的代码。

  
 
解决方案
 <$ p $  p>  continue_element.visible？

不会引发错误，它只是要返回一个布尔值。它听起来像这个元素实际上并没有结束可见，这仍然会引起错误，无论隐式等待：

 提高除非continue_element.visible？

此外，更好的模式是：

  continue.wait_until_present

或

  continue.when_present.click

.present？只是指 .exists？&& .visible？这其实是你想要的，这个模式会给你一个更好的错误信息。

This is the code which is failing for me.

link(:continue, :text => 'Continue Shopping')

def verify_cart
    wait_until(60) do
      continue_element.visible?
    end
  end

To make it work I have tried solutions here:Inconsistently getting error (Watir::Wait::TimeoutError)and Timeout::Error in Rails application using Watir but none worked for me.

I have also tried by increasing the time.

Then I tried by increasing the at implicit wait from 3 seconds to 20 seconds and instead of using wait_until block I simply used .visible? and it worked.

link(:continue, :text => 'Continue Shopping')

continue_element.visible?

 #def verify_cart
 #   wait_until(60) do
 #     continue_element.visible?
 #   end
 # end

Now question is when element was there why wait_until kept on failing?

解决方案

continue_element.visible?

is not going to raise an error, it is just going to return a boolean. It sounds like this element doesn't actually end up visible, and this would still raise the error regardless of the implicit wait:

raise unless continue_element.visible?

Also, a better pattern for this is:

continue.wait_until_present

continue.when_present.click

.present? just means .exists? && .visible? which is actually what you want, and this pattern will give you a better error message.

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