问题描述
我有两个窗口:父
和弹出窗口
。显然 parent
引用了 popup
。现在在弹出窗口
我有一个函数说
I have two windows: the parent
and the popup
. Obviously parent
has a reference to popup
. Now in popup
I have a function say
function test() { alert('test'); }
我想在父$ c $中调用此函数c>,类似
popup.test();
。有没有办法做到这一点?我确实知道如何做到这一点。只是声明
and I want to call this function in parent
, something like popup.test();
. Is there a way to do that? I do know how to do that the other way around. Just declaring
window.test = function() { alert('test'); }
并且调用 window.opener.test();
在弹出窗口工作正常。但是这在我的情况下不起作用(我认为因为 window.opener
对象是一个引用,但是 window.open
和窗口
在弹出窗口
中并不真正相关)。任何想法?
and calling window.opener.test();
in popup works fine. However this does not work in my case (I think because the window.opener
object is a reference, but window.open
and window
in popup
are not really related). Any ideas?
推荐答案
这实际上取决于您为弹出窗口定义函数的上下文。假设您将函数/数据附加到弹出窗口的窗口
对象,您可以从 window.open返回的窗口句柄中访问它。 code>(窗口句柄是
窗口
弹出对象):
It really depends on the context where you defined the function for the popup window. Assuming you attached the functions/data to the window
object of the popup window, you can access it from the window handle returned by window.open
(the window handle is the window
object for the popup):
var w = window.open(somelocation,''); //has a function on `window` called "test"
w.test();
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