问题描述
我有以下字符串
set str=aaaaa,bbbbb,ccccc,dddd
我需要更换一切从第一，（逗号），直到字符串的结尾。但我不知道怎么的字符串开始。
I need to replace everything from the first , (comma) till the end of string. but I don't know how the string starts.
我不能使用通配符*，因为它是不是在字符串的开始，所以类似的东西 -
I can't use the * wildcard as it is not in the start of string, so something like that -
set str=%str:,*=% >>>> Will not work
任何想法？它必须在一个批处理脚本的
Any ideas ? it must be in a batch script
推荐答案
有就是避免了FOR循环一个非常简单而快速的解决方案：使用搜索和替换在每个逗号注入级联REM命令： - ）
There is a very simple and fast solution that avoids a FOR loop: use search and replace to inject a concatenated REM command at each comma :-)
@echo off
set str=aaaaa,bbbbb,ccccc,dddd
set "str=%str:,="&rem %
echo str=%str%
说明
下面是code的重要防线，任何扩大发生之前：
Here is the the important line of code, before any expansion takes place:
set "str=%str:,="&rem %
这是该行被转换成变量扩展后：
And here is what the line is transformed into after variable expansion:
set "str=aaaaa"&rem bbbbb"&rem ccccc"&rem dddd
它成为一个SET语句，然后是REM语句。在＆安培; 运营商可将多个命令在一行结合起来。世界上只有一个REM语句，因为第一个REM之后一切都被认为此言的一部分。
It becomes a SET statement, followed by a REM statement. The & operator allows you to combine multiple commands on one line. There is only one REM statement because everything after the first REM is considered part of the remark.
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