问题描述
我想有一个问题，我在awk的帮助或方向。
I would like to have help or direction on a problem I have in awk.
我有超过5场制表符分隔的文件。我想输出不计首5个字段的字段。
I have a tab-delimited file with more than 5 fields. I want to output the fields excluding the first 5 fields.
你能告诉如何写awk脚本来完成这项任务？
Could you please tell how to write an awk script to accomplish this task?
最佳，
jianfeng.mao
Best,jianfeng.mao
请注意以下几点那种评论：
Do Note the following kind comment:
有在我的文件很多领域。不同的线路具有不同数量的域。每行中的字段的数目是不标准。
There are many fields in my files. Different lines have a different number of fields. The number of fields per line is not standard.
推荐答案
我同意matchew的建议，使用削减：这是这个工作的工具。但是，如果这仅仅是要成为一个更大的 AWK 脚本的一部分，这里是如何做到这一点：
I agree with matchew's suggestion to use cut: it's the right tool for this job. But if this is just going to become a part of a larger awk script, here's how to do it:
awk -F "\t" '{ for (i=6; i<=NF; ++i) $(i-5) = $i; NF = NF-5; print; }
这篇关于打印字段'N'到行尾的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！