以编程方式为Spring创建JNDI

以编程方式为Spring创建JNDI

本文介绍了以编程方式为Spring创建JNDI DataSource的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有一个现有的基于Spring网络的应用程序,其中包含使用JNDI定义的数据源,我正在尝试创建一个独立的应用程序来使用这些bean。如何在独立应用程序中以编程方式创建JNDI条目和数据库属性?

I have an existing Spring web-based application that has datasources defined using JNDI, and I'm trying to create a standalone app to use the beans. How can I create the JNDI entry and database properties programmatically in the standalone application?

<bean id="myDataSource" class="org.springframework.jndi.JndiObjectFactoryBean">
    <property name="jndiName" value="java:comp/env/jdbc/MyDS" />
</bean>

    public static void main(String[] args) {

      // this throws an error since the JNDI lookup fails - can I programmatically define the database properties here?

    ClassPathXmlApplicationContext ctx = new  ClassPathXmlApplicationContext("applicationContext.xml");

    UserService userService = ctx.getBean(UserService.class);
    User user = userService.findUserById("jdoe");

    System.out.println("display name: " + user.getDisplayName());
}

编辑:

我尝试了类似的东西,但现在收到错误javax.naming.NoInitialContextException:需要在环境或系统属性中指定类名

I tried something like this, but am now getting the error "javax.naming.NoInitialContextException: Need to specify class name in environment or system property"

public static void main(String[] args) {
    setupJNDI();

    ClassPathXmlApplicationContext ctx = new  ClassPathXmlApplicationContext("applicationContext.xml");

    UserService userService = ctx.getBean(UserService.class);
    User user = userService.findUserById("jdoe");

    System.out.println("display name: " + user.getDisplayName());
}


private static void setupJNDI() {
    InitialContext ic;
    try {
        ic = new InitialContext();
        ic.createSubcontext("java:");
        ic.createSubcontext("java:/comp");
        ic.createSubcontext("java:/comp/env");
        ic.createSubcontext("java:/comp/env/jdbc");
        SQLServerConnectionPoolDataSource myDS = new SQLServerConnectionPoolDataSource();
        opaDS.setServerName("myserver");
        opaDS.setPortNumber(1433);
        opaDS.setUser("user");
        opaDS.setPassword("password");

        ic.bind("java:/comp/env/jdbc/MyDS", myDS);
    } catch (NamingException e) {
        e.printStackTrace();
    }
}


推荐答案

org.springframework.test 依赖项通过:

The org.springframework.test dependency has support for that via the SimpleNamingContextBuilder:

// First create the mock JNDI tree and bind the DS
SimpleNamingContextBuilder builder = new SimpleNamingContextBuilder();
DataSource ds = new ComboPooledDataSource();
ds.setDriverClass( ... ); // etc. for uid, password, url
builder.bind( "java:comp/env/jdbc/MyDS" , ds );
builder.activate();

// Then create the Spring context, which should now be able
// to resolve the JNDI datasource
ApplicationContext context = new ClassPathXmlApplicationContext( "..." );

这应该有效。

干杯,

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08-23 00:03