php json_encode& jQuery parseJSON单引号问题

问题描述

我搜索并阅读了大多数相关主题，但这些并不是我想要的.

I searched and read most of the related topics, but they weren't what I was looking for.

我有一个json_encode PHP函数的JSON编码字符串:

I've a JSON enocded string with json_encode PHP function:

{"casts":["Matthew Modine","Adam Baldwin","Vincent D'Onofrio"],"year":1987}

在测试的情况下，我也使用jQuery将值也放入适当的字段中:

I'm working with jQuery to put the values in appropriate fields too, in the case of testing I did the below:

<script>
var obj = jQuery.parseJSON('<?=$data?>');
console.log(obj);
</script>

假设$ data是这样的:

Suppose that $data is this:

$data =
<<<END
{"casts":["Matthew Modine","Adam Baldwin","Vincent D'Onofrio"],"year":1987}
END;

在这种情况下，Google chrome控制台会产生什么:

What Google chrome console produces in this case:

Uncaught SyntaxError: Unexpected identifier

但是，当我更改JSON编码的字符串时-在单引号中添加反斜杠:

However when I make a change in JSON encoded string - adding Backslash to single quote :

{"casts":["Matthew Modine","Adam Baldwin","Vincent D\'Onofrio"],"year":1987}

控制台输出正常:

Object {casts: Array[3], year: 1987}
casts: Array[3]
year: 1987

问题:控制台中是否会出现此错误?我认为转义'或将'替换为\'会很脏！

The question: is this error in console expected? I think escaping or replacing ' with \' will be so dirty!

已更新

UPDATED

实际上 $ data 值来自json_encode($var)，而$ var是一个数组！

Actually $data value comes from a json_encode($var) and $var is an array!

$data = json_encode($var);

推荐答案

在PHP字符串文字中将其转义.然后将其作为简单的'插入到PHP字符串中.

That escapes it in the PHP string literal. It is then inserted into the PHP string as a simple '.

如果要在将其插入JavaScript之前对其进行转义，则需要在字符串中添加斜杠，以得到的 out (或者，因为您没有使用该字符串(应该是！)您手动构建的JSON字符串).

If you want to escape it before inserting it into JavaScript then you need to add slashes to the string you get out of json_encode (or rather, since you aren't using that (you should be!) the JSON string you build by hand).

那是您需要做的更多工作.真正的解决方案是记住JSON是JavaScript文字语法的子集:

That is more work then you need though. The real solution is to remember that JSON is a subset of JavaScript literal syntax:

var obj = <?=$data?>;

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