如何在ajax发布回调后刷新KendoUi网格 | 如何在ajax发布回调后刷新KendoUi网格

本文介绍了如何在ajax发布回调后刷新KendoUi网格的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

如何在ajax发布成功后刷新kendo ui网格?这是我的网格ajax帖子:

 var newUser = {
                    UserId: 0,
                    UserLoginName: currentRecord.UserLoginName,
                    UserDisplayName: currentRecord.UserDisplayName
                };
                //insert selected rows using DataSource insert method
                destinationGrid.dataSource.insert(newRecord);
                //ajax post to server
                var url = '@Url.Action("CreateUser", "ManageUsers")';
                $.post(url, { loginid: currentRecord.UserLoginName, name: currentRecord.UserDisplayName, role: roleSelected }, function (result) {
                    if (result.Success) {
        **////grid is not refreshing as I want to refersh the grid again from database**
                        destinationGrid.dataSource.read();
                    }

                });
            }

解决方案

这只是示例

 $.ajax({
          url: '@Url.Action("NewGridView", "Test")',
          type: "Post",
          data: { sampleItem: sampleItem, sampleCode: sampleCode, sampledescription: sampledescription },
          dataType: 'json',
          success: function (result) {

     $('#gridName').data("kendoGrid").dataSource = new kendo.data.DataSource({ data: result });
     $('#gridName').data("kendoGrid").dataSource.read();
     $('#gridName').data("kendoGrid").refresh();
}
});

控制器

 public JsonResult NewGridView(string sampleItem, string sampleCode, string sampledescription)
        {

        List<SampleModel> sampleAddList = new List<SampleModel>();
        SampleModel sampleAdd = new SampleModel();
        sampleAdd.SampleCode = sampleCode;
        sampleAdd.SampleDescription = sampledescription;
        sampleAdd.SampleItems = sampleItem;

        sampleAddList.Add(sampleAdd);
        var result = sampleAddList;
       return Json(result, JsonRequestBehavior.AllowGet);
}

如果您需要在执行控制器操作后立即刷新网格，

post success

中的

$('#gridName').data("kendoGrid").dataSource = new kendo.data.DataSource({ data: result });

How to refresh the kendo ui grid after a ajax post is successful?Here is my grid ajax post:

 var newUser = {
                    UserId: 0,
                    UserLoginName: currentRecord.UserLoginName,
                    UserDisplayName: currentRecord.UserDisplayName
                };
                //insert selected rows using DataSource insert method
                destinationGrid.dataSource.insert(newRecord);
                //ajax post to server
                var url = '@Url.Action("CreateUser", "ManageUsers")';
                $.post(url, { loginid: currentRecord.UserLoginName, name: currentRecord.UserDisplayName, role: roleSelected }, function (result) {
                    if (result.Success) {
        **////grid is not refreshing as I want to refersh the grid again from database**
                        destinationGrid.dataSource.read();
                    }

                });
            }

解决方案

This is just example

 $.ajax({
          url: '@Url.Action("NewGridView", "Test")',
          type: "Post",
          data: { sampleItem: sampleItem, sampleCode: sampleCode, sampledescription: sampledescription },
          dataType: 'json',
          success: function (result) {

     $('#gridName').data("kendoGrid").dataSource = new kendo.data.DataSource({ data: result });
     $('#gridName').data("kendoGrid").dataSource.read();
     $('#gridName').data("kendoGrid").refresh();
}
});

Controller

 public JsonResult NewGridView(string sampleItem, string sampleCode, string sampledescription)
        {

        List<SampleModel> sampleAddList = new List<SampleModel>();
        SampleModel sampleAdd = new SampleModel();
        sampleAdd.SampleCode = sampleCode;
        sampleAdd.SampleDescription = sampledescription;
        sampleAdd.SampleItems = sampleItem;

        sampleAddList.Add(sampleAdd);
        var result = sampleAddList;
       return Json(result, JsonRequestBehavior.AllowGet);
}

if you need to refresh your grid as soon as complate controller action do this,

$('#gridName').data("kendoGrid").dataSource = new kendo.data.DataSource({ data: result }); in your post success

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