问题描述
我想废弃的网站是:
我的代码:
from bs4 import BeautifulSoup从 urllib.request 导入 urlopen 作为 uReqfrom selenium import webdriver;导入时间from selenium.webdriver.common.by import By从 selenium.webdriver.support.ui 导入 WebDriverWait从 selenium.webdriver.support 导入 expected_conditions 作为 EC从 selenium.webdriver.common.desired_capabilities 导入 DesiredCapabilitiesfirefox_capabilities = DesiredCapabilities.FIREFOXfirefox_capabilities['marionette'] = Truefirefox_capabilities['binary'] = '/etc/firefox'驱动程序 = webdriver.Firefox(capabilities=firefox_capabilities)url = "http://www.mouthshut.com/mobile-operators/Reliance-Jio-reviews-925812061"driver.get(url)等待 = WebDriverWait(驱动程序,10)汤=BeautifulSoup(driver.page_source,"lxml")容器 = 汤.findAll("ul",{"class":"pages table"})容器 [0] = 汤.findAll("li")li_len = len(容器[0])对于soup.find("ul",{"class":"pages table"}) 中的项目:li_text = item.select("li")[li_len].text打印(li_text:{}
".格式(li_text))驱动程序退出()
我需要帮助找出获取最后页码的代码中的错误.另外,如果有人提供相同的替代解决方案并建议实现我的意图的方法,我将不胜感激.
如果你想得到上面链接的最后一个页码继续进行,就是499
您可以使用 Selenium
或 Beautifulsoup
如下:
硒:
from selenium import webdriverdriver = webdriver.Firefox(executable_path=r'C:UtilityBrowserDriversgeckodriver.exe')url = "http://www.mouthshut.com/mobile-operators/Reliance-Jio-reviews-925812061"driver.get(url)element = driver.find_element_by_xpath("//div[@class='row pagination']//p/span[contains(.,'Reviews on Reliance Jio')]")driver.execute_script("返回参数[0].scrollIntoView(true);", element)print(driver.find_element_by_xpath("//ul[@class='分页表']/li/ul[@class='pages table']//li[last()]/a").get_attribute("innerHTML"))驱动程序退出()
控制台输出:
499
美汤:
导入 bs4从 bs4 导入 BeautifulSoup 作为汤从 urllib.request 导入 urlopen 作为 uRequrl = "http://www.mouthshut.com/mobile-operators/Reliance-Jio-reviews-925812061"uClient = uReq(url)page_html = uClient.read()uClient.close()page_soup = 汤(page_html,html.parser")container = page_soup.find("ul",{"class":"pages table"})all_li = container.findAll("li")last_div = 无对于 all_li:pass 中的 last_div如果 last_div:content = last_div.getText()打印(内容)
控制台输出:
499
The website I want to scrap is :
http://www.mouthshut.com/mobile-operators/Reliance-Jio-reviews-925812061
I want to get the last page number of the above the link for proceeding, which is 499 while taking the screenshot.
My code :
from bs4 import BeautifulSoup
from urllib.request import urlopen as uReq
from selenium import webdriver;import time
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.desired_capabilities import DesiredCapabilities
firefox_capabilities = DesiredCapabilities.FIREFOX
firefox_capabilities['marionette'] = True
firefox_capabilities['binary'] = '/etc/firefox'
driver = webdriver.Firefox(capabilities=firefox_capabilities)
url = "http://www.mouthshut.com/mobile-operators/Reliance-Jio-reviews-925812061"
driver.get(url)
wait = WebDriverWait(driver, 10)
soup=BeautifulSoup(driver.page_source,"lxml")
containers = soup.findAll("ul",{"class":"pages table"})
containers[0] = soup.findAll("li")
li_len = len(containers[0])
for item in soup.find("ul",{"class":"pages table"}) :
li_text = item.select("li")[li_len].text
print("li_text : {}
".format(li_text))
driver.quit()
I need help to figure out the error in my code for getting the last page number. Also, I would be grateful if someone give the alternate solution for the same and suggest ways to achieve my intention.
If you want to get the last page number of the above the link for proceeding, which is 499
you can use either Selenium
or Beautifulsoup
as follows :
Selenium :
from selenium import webdriver
driver = webdriver.Firefox(executable_path=r'C:UtilityBrowserDriversgeckodriver.exe')
url = "http://www.mouthshut.com/mobile-operators/Reliance-Jio-reviews-925812061"
driver.get(url)
element = driver.find_element_by_xpath("//div[@class='row pagination']//p/span[contains(.,'Reviews on Reliance Jio')]")
driver.execute_script("return arguments[0].scrollIntoView(true);", element)
print(driver.find_element_by_xpath("//ul[@class='pagination table']/li/ul[@class='pages table']//li[last()]/a").get_attribute("innerHTML"))
driver.quit()
Console Output :
499
Beautifulsoup :
import bs4
from bs4 import BeautifulSoup as soup
from urllib.request import urlopen as uReq
url = "http://www.mouthshut.com/mobile-operators/Reliance-Jio-reviews-925812061"
uClient = uReq(url)
page_html = uClient.read()
uClient.close()
page_soup = soup(page_html, "html.parser")
container = page_soup.find("ul",{"class":"pages table"})
all_li = container.findAll("li")
last_div = None
for last_div in all_li:pass
if last_div:
content = last_div.getText()
print(content)
Console Output :
499
这篇关于使用 BeautifulSoup 和 Selenium 抓取一个网站的多个网页的内容的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!