NameError:未定义全局名称“文本"

问题描述

我有一个 python 代码片段，它使用凯撒密文将 Mac 地址转换为另一个代码:代码如下:

I have a python code snippet that coverts the Mac address to another code using caesar ciphertext: The code is given below:

import uuid
def getmac():
  mac_num = hex(uuid.getnode()).replace('0x', '').upper()
  mac = ''.join(mac_num[i : i + 2] for i in range(0, 11, 2))
  return mac

plaintext = getmac()
alphabet = "ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789"
key = 1
cipher = ''

for c in plaintext:
    if c in alphabet:
      cipher += alphabet[(alphabet.index(c) + key +3)%(len(alphabet))]
print('Code:' + cipher)

这可以正常工作，因为它将代码打印到 Python shell，但是当我使用 TKinter 库编辑相同的代码时，出现连接和其他错误，TKinter 库中使用的代码如下:在这个片段中，程序的功能是相同的，但是我只想从用户输入 mac 地址，当他点击提交时，代码会提示给他:

This works proper as it prints out the code to the Python shell, however when i Edit the same code with TKinter library, I get concatenation and other errors , The code used in TKinter lib is given below:In this snippet the function of the program is same ,however i just want the mac address to be input from the user and when he clicks on submit ,the code is prompted to him:

import uuid
from Tkinter import *

root = Tk()

root.title("Code Generator")
root.geometry("250x200+200+100")
root.resizable(width=False, height=False)
cipher = ''


Label(root, text='Mac Address:').grid(row=0, sticky=W, padx=4)
Entry(root).grid(row=0, column=1, sticky=E, pady=4)

Label(root, text="Code:").grid(row=1, sticky=W, padx=4)
hlbl = Label(root, text=cipher,  width=20)
hlbl.grid(row=0, column=2, sticky=E, pady=4)


def get_it():
 alphabet = "ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789"
  for c in text:
    if c in alphabet:
      cipher += alphabet[(alphabet.index(c) + key + 2) % (len(alphabet))]

Button(root, text="Submit", command=get_it).grid(row=2, column=1)
root.mainloop()

当我运行程序时，我得到了这个:

当我输入随机文本并单击提交时，我得到以下信息:

我应该做哪些改变?

when i run the program i get this:

When i enter a random text and click submit i get this:

What changes should i make?

推荐答案

首先你需要为 tkinter 命名 Entry 以便你以后可以引用它，然后使用 get> 获取 Entry 文本的方法.

First you need to name the tkinter Entry so you can reference to it later, then use the get method to get the Entry text.

这是修改后的代码；

import uuid
from Tkinter import *

root = Tk()

root.title("Code Generator")
root.geometry("250x200+200+100")
root.resizable(width=False, height=False)
key = 1
cipher = ''

label_text = StringVar()
#label_text.set(cipher)


Label(root, text='Mac Address:').grid(row=0, sticky=W, padx=4)
entry = Entry(root)
entry.grid(row=0, column=1, sticky=E, pady=4)

Label(root, text="Code:").grid(row=1, sticky=W, padx=4)
hlbl = Label(root, textvariable=label_text,  width=20)
hlbl.grid(row=1, column=1, sticky=E, pady=4)


def get_it():
    global key, cipher
    alphabet = "ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789"
    text =  entry.get() # get contents of entry
    for c in text:
        if c in alphabet:
            cipher += alphabet[(alphabet.index(c) + key + 2) % (len(alphabet))]
    label_text.set(cipher)

Button(root, text="Submit", command=get_it).grid(row=2, column=1)
root.mainloop()

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