阅读xml问题

问题描述

对不起，我在其他论坛而不是c#上发布了我的问题.

Sorry i posted my issues in another forum instead of c#.

您能帮忙这个打击吗?

https://social.msdn.microsoft.com/Forums/zh-CN/270481ae-3734-4e39-8f61-1e11e91e4f82/read-xml?forum=linqtosql

https://social.msdn.microsoft.com/Forums/en-US/270481ae-3734-4e39-8f61-1e11e91e4f82/read-xml?forum=linqtosql

喜欢dotnet

推荐答案

List<XElement> lstuser = xelement.Elements().ToList();
int count = lstuser.Count; // = 2

如果要使用列表<用户>您可以使用LINQ Select方法为每个返回的XElement创建一个新的User对象:

If you want a List<User> you could use the LINQ Select method to create a new User object for each returned XElement:

List<User> lstuser = xelement.Elements().Select(element => new User()
            {
                Name = element.Element("Name").Value,
                BirthTime = element.Element("BirthTime").Value,
            }).ToList();

或者如果您需要UserList:

Or if you want a UserList:

            UsersList userList = new UsersList()
            {
                User = xelement.Elements().Select(element => new User()
                {
                    Name = element.Element("Name").Value,
                    BirthTime = element.Element("BirthTime").Value,
                }).ToList()
            };

希望有帮助.

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