Fortran中的阵列数组

问题描述

我试图定义一个数组数组。
我已经定义：

  
最简单的方法可能是将 s  3数组，也许 
 
 整型，维（3,2,2）:: s 
  
，然后您可以编写语句，如 
 
 
  s（1，：，:) = x 
s（2，：，:) = y 
 ... 
  
这是在Fortran中实现一组数组的自然方法。另一种可能更吸引你的选择是： 
 
 
  type :: twodarray 
 integer，dimension（ 2,2）:: elements 
 end type twodarray 
 
 type（twodarray），dimension（3）:: s 
 
s（1）％elements = x 
  
如果您不喜欢 s（1）％元素= x 你可以为你的类型 twodarray 重新定义操作 = ，我没有现在可以为您编写代码。
 
I am trying to define a array of arrays.I have defined: 
  integer,dimension(2,2):: &
    x=reshape(source= (/0,1,1,0/),  shape=(/2,2/)), &
    y=reshape(source= (/1,0,0,1/),  shape=(/2,2/)), &
    z=reshape(source= (/1,1,1,1/),  shape=(/2,2/))
I want to define an array, say, s(3),  of which, (x/y/z) are components, i.e. 
s(1)=x
s(2)=y
and s(3)=z
how can I achieve that? 
 解决方案 
The simplest approach might be to define s as a rank-3 array, perhaps
integer, dimension(3,2,2) :: s
and then you can write statements such as
s(1,:,:) = x
s(2,:,:) = y
...
This is the 'natural' way to implement an array of arrays in Fortran.  An alternative, which might appeal to you more would be something like:
type :: twodarray
   integer, dimension(2,2) :: elements
end type twodarray

type(twodarray), dimension(3) :: s

s(1)%elements = x
If you don't like the wordiness of s(1)%elements = x you could redefine the operation = for your type twodarray, I don't have time right now to write that code for you.
                        
这篇关于Fortran中的阵列数组的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！