问题描述
我有一个供稿，其提供的供稿格式如下： 10月14日星期五
I have a feed which gives feed in the following format: "Fri 14 Oct"
我想看看今天的日期是否与供稿中的日期匹配。我的问题是今天日期的格式/
I want to see if today's date matches the date from the feed. My problem is the format of today's date/
$today = date("d m");
这将输出17 10。
什么是格式化$ today的最佳方法，以便它输出Day（简写）空格日期（数字）Month（简写）？
What is the best way to format $today so that it outputs Day (shorthand) space date (number) Month (shorthand) ?
推荐答案
如何：
$today = date("D j M");
如参考手册。
无论如何，除非您100％确信，否则应该注意时区问题
Anyway you should be aware of timezone issues unless you are 100% sure that your server is in the same timezone of the feed you are comparing.
我会采用不同的方法，但是您可以解析该Feed的使用的日期，它也了解时区，然后进行比较加上今天的日期。
I would follow a different approach though, you can parse the feed's date using DateTime::createFromFormat() which also understand timezones, and then compare it with today's date.
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