将Large Integer txt文件读入2D数组

问题描述

试图创建一个程序来处理大型文本文件，并将其填充到行+列中。最终，我将不得不走计算机的最佳之路，但是在实现一个可以存储值的数组时遇到麻烦。

Attempting to create a program that reasons in a large Text File and filled them into Rows + Columns. Eventually I'll have to computer best path but having trouble just implementing an Array that can store the values.

#include <stdio.h>
#include <stdlib.h>

//max number of characters to read in a line. //MAXN=5 means 4 chars are read, then a \0 added in fgets.  See reference for functionality

#define  MAXN  100L
int main(void)   //char** argv also ok {
    int i=0, totalNums, totalNum,j=0;
    size_t count;
    int numbers[100][100];
    char *line = malloc(100);
    FILE* inFile ;
    inFile = fopen("Downloads/readTopoData/topo983by450.txt", "r");   //open a file from user for reading

    if( inFile == NULL) {  // should print out a reasonable message of failure here
        printf("no bueno \n");
        exit(1);
    }

    while(getline(&line,&count, inFile)!=-1) {
        for(;count>0; count--,j++)
            sscanf(line, "%d", &numbers[i][j]);
            i++;
    }

    totalNums = i;
    totalNum = j;
    for(i=0;i<totalNums; i++){
      for(j=0;j<totalNum;j++){
        printf("\n%d", numbers[i][j]);
       }
    }
    fclose(inFile);
    return 0;
}

推荐答案

计数不会告诉您如何有很多数字。另外：sscanf（line，％d，& numbers [i] [j]）;

count does not tell you how many numbers there are. Further: sscanf(line, "%d", &numbers[i][j]); will just scan the same number every time.

因此，这

    for(;count>0; count--,j++)
        sscanf(line, "%d", &numbers[i][j]);

应该类似于：

    j = 0;
    int x = 0;
    int t;
    while(sscanf(line + x, "%d%n", &numbers[i][j], &t) == 1)
    {
        x += t;
        ++j;
    }

其中 x 在一起％n 可以帮助您在扫描数字后移动到字符串的新位置。

where x together with %n helps you move to a new position in the string when a number has been scanned.

这里是扫描字符串中数字的简化版本：

Here is a simplified version that scans for numbers in a string:

#include <stdio.h>

int main(void) {
    char line[] = "10 20 30 40";
    int numbers[4];
    int j = 0;
    int x = 0;
    int t;
    while(j < 4 && sscanf(line + x, "%d%n", &numbers[j], &t) == 1)
    {
        x += t;
        ++j;
    }
    for(t=0; t<j; ++t) printf("%d\n", numbers[t]);
    return 0;
}

输出：

10
20
30
40

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