如何打印文字字符串"$ 1"在bash脚本中?

问题描述

我要打印一个名为"$ 1"的字符串.但是，当我用echo执行此操作时，它会打印等于"$ 1"变量的字符串.如何像字符串一样打印"$ 1"?

I want to print string called "$1". But when I do this with echo it prints string which equals to "$1" variable. How can I print "$1" just like string?

例如:

set -- "output"  # this sets $1 to be "output"
echo $1          # ==> output

但是我想要这个:

echo $1      # ==> $1

推荐答案

您必须转义 $ 才能显示它:

You have to escape the $ to have it shown:

$ echo "\$1"

或者，正如JeremyP在注释中指出的那样，只需使用单引号使 $ 1 的值不会扩展:

or, as noted by JeremyP in comments, just use single quotes so that the value of $1 does not get expanded:

$ echo '$1'

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