为什么我会收到“未定义的参考"?静态成员变量的链接错误?

问题描述

我有此代码

文件:Gnome.cpp

#include "Living.h"

class Gnome : public Living {
public:
    Gnome();
    void drawObjects();
};


Gnome::Gnome()
{
  // **** The line below is where the error occurs ****
  spriteImg = new Sprite("graphics/gnome.bmp");
  loaded = true;
}

文件:Living.h

#include <iostream>
#include "Sprite.h"


using namespace std;

class Sprite;

class Living {
protected:
    int x,y;
    static Sprite *spriteImg; //= NULL;
    bool loaded;

    void reset();

public:
    Living();
    ~Living();
    int getX();
    void setX(int _x);
    int getY();
    void setY(int _y);
    void virtual drawObjects() =0;
};

但是当我尝试构建它时，链接器显示此错误:

But when I try to build it, the linker shows this error:

我不知道该如何解决-有什么问题?

I have no idea how to fix this -- what's the problem?

推荐答案

您声明了spriteImg，但从未对其进行定义.在living.cpp中，尝试添加以下内容:

You declared spriteImg, but never defined it. In living.cpp, try adding the following:

Sprite* Living::spriteImg = NULL;

自声明以来，编译器允许您对其进行引用，并期望链接程序将解析该引用.由于永远都没有定义，因此链接器无法这样做，并且会抱怨.

Since you declared it, the compiler allows you to reference it, and expects that the linker will resolve the reference. Since there is never a definition, the linker can't do so, and it complains.

编辑:如果您想了解更多有关此处发生的情况的信息，请研究诸如C ++中的编译单元"，编译"，链接"和静态类变量"之类的主题."

if you would like to learn more about what's going on here, research topics such as "compilation units," "compiling," "linking," and "static class variables in C++."

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