问题描述
是否可以输入字符并取回unicode值?例如,我可以将⽇放在html中以输出⽇",是否可以将该字符作为函数的参数并获得数字作为输出而无需构建unicode表?
Is it possible to input a character and get the unicode value back? for example, i can put ⽇ in html to output "⽇", is it possible to give that character as an argument to a function and get the number as an output without building a unicode table?
$val = someFunction("⽇");//returns 12103
还是相反?
$val2 = someOtherFunction(12103);//returns "⽇"
我希望能够将实际字符输出到页面上而不是代码中,并且如果可能的话,我也希望能够从字符中获取代码.我最想要的是php.net/manual/en/function.mb-decode-numericentity.php,但是我无法正常工作,这是我需要的代码还是在错误的轨道上?
I would like to be able to output the actual characters to the page not the codes, and I would also like to be able to get the code from the character if possible.The closest I got to what I want is php.net/manual/en/function.mb-decode-numericentity.php but I cant get it working, is this the code I need or am I on the wrong track?
推荐答案
function _uniord($c) {
if (ord($c{0}) >=0 && ord($c{0}) <= 127)
return ord($c{0});
if (ord($c{0}) >= 192 && ord($c{0}) <= 223)
return (ord($c{0})-192)*64 + (ord($c{1})-128);
if (ord($c{0}) >= 224 && ord($c{0}) <= 239)
return (ord($c{0})-224)*4096 + (ord($c{1})-128)*64 + (ord($c{2})-128);
if (ord($c{0}) >= 240 && ord($c{0}) <= 247)
return (ord($c{0})-240)*262144 + (ord($c{1})-128)*4096 + (ord($c{2})-128)*64 + (ord($c{3})-128);
if (ord($c{0}) >= 248 && ord($c{0}) <= 251)
return (ord($c{0})-248)*16777216 + (ord($c{1})-128)*262144 + (ord($c{2})-128)*4096 + (ord($c{3})-128)*64 + (ord($c{4})-128);
if (ord($c{0}) >= 252 && ord($c{0}) <= 253)
return (ord($c{0})-252)*1073741824 + (ord($c{1})-128)*16777216 + (ord($c{2})-128)*262144 + (ord($c{3})-128)*4096 + (ord($c{4})-128)*64 + (ord($c{5})-128);
if (ord($c{0}) >= 254 && ord($c{0}) <= 255) // error
return FALSE;
return 0;
} // function _uniord()
和
function _unichr($o) {
if (function_exists('mb_convert_encoding')) {
return mb_convert_encoding('&#'.intval($o).';', 'UTF-8', 'HTML-ENTITIES');
} else {
return chr(intval($o));
}
} // function _unichr()
这篇关于我可以使用php获取字符的unicode值,反之亦然吗?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!