问题描述
我试图在单击反应选择的选定值"元素时显示弹出窗口，如下所示:
I am trying to display a popover on click over a react-select selected value element as follow :
当我单击弹出窗口触发器时，会发生我的问题，下拉菜单也会打开，而且弹出窗口也...我只想打开弹出窗口，我尝试了 e.nativeElement.stopPropagation ，e.stopPropagation ， e.preventDefault 等都没有成功.这是一个沙箱，如果您想知道我是怎么做的以及如何重现该问题.
My issue happens when I click on the popover trigger, the dropdown opens and the popover too... I just want to open the popover, I tried e.nativeElement.stopPropagation, e.stopPropagation, e.preventDefault and so on without success. Here is a sandbox If you want to know how I did this and how to reproduce the issue.
https://codesandbox.io/s/pjv7vmlv3j
感谢您的帮助
推荐答案
好吧，我找到了一种取消事件的方法.我只需在< Select/> 上添加 onValueClick 道具，然后在其中放置 stopPropagation ！
Well I found a way to cancel the event. I just add an onValueClick prop to the <Select /> and put the stopPropagation there!
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