C＃中的“跨线程操作错误”需要帮助

问题描述

在以下代码中 MessageReceived 与 label1 不同的线程，当尝试访问它时，我会得到这个错误：

  foo.MessageReceived + =新代理.MessageReceivedHandler（foo_MessageReceived）; 
 
 void foo_MessageReceived（message message）
 {
 label1.Text = message.Body; 
} 
  

我如何解决这个问题？ >

更多：显然我需要使用委托和 code>，但是我不知道如何更详细地解释？

解决方案

永远确定您在主线程（GUI线程）上更新您的GUI。

foo.MessageReceived + = new Agent.MessageReceivedHandler（foo_MessageReceived）;

  public delegate void MyDelegate（Message msg）; 
 void foo_MessageReceived（message message）
 {
 if（InvokeRequired）
 {
 BeginInvoke（new MyDelegate（foo_MessageReceived），new object [] {m​​essage}）; 
} 
 else 
 {
 label1.Text = message.Body; 
} 
} 
  

In the following code MessageReceived is on a different thread to label1 and when trying to access it I will get this error:

foo.MessageReceived += new Agent.MessageReceivedHandler(foo_MessageReceived);

void foo_MessageReceived(Message message)
{
   label1.Text = message.Body;
}

How can I solve this?

More: apparently I need to use delegate and invoke, but I don't know how, can you please explain in more detail?

解决方案

Make always sure you update your GUI on the main thread (GUI thread).

foo.MessageReceived += new Agent.MessageReceivedHandler(foo_MessageReceived);

public delegate void MyDelegate(Message msg);
void foo_MessageReceived(Message message)
{
   if (InvokeRequired)
   {
      BeginInvoke(new MyDelegate(foo_MessageReceived),new object[]{message});
   }
   else
   {
      label1.Text = message.Body;
   }
}

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