问题描述
我要在C和有关于使用指针常量使用的问题。我了解以下code：
I am going over C and have a question regarding const usage with pointers. I understand the following code:
const char *someArray
这是定义一个指向类型char和在常量修改意味着一个指针存储在的someArray 不能改变。然而，什么是下面的意思吗？
This is defining a pointer that points to types of char and the const modifier means that the values stored in someArray cannot be changed. However, what does the following mean?
char * const array
这是指定一个参数，该参数是一个字符指针到名为阵的数组是的另一种方式常量，不能进行修改？
Is this an alternate way of specifying a parameter that is a char pointer to an array named "array" that is const and cannot be modified?
最后，这是什么意思的组合：
Lastly, what does this combination mean:
const char * const s2
有关的参考，这些是从的Deitel C语言编程的书采取的第7章，所有这些被用作传递给函数的参数。
For reference, these are taken from the Deitel C programming book in Chapter 7 and all of these are used as parameters passed to functions.
推荐答案
为const char * 是，如你所说，一个指向一个char，在那里你可以不改变字符的值（至少不是通过指针（没有铸造常量性远））。
const char* is, as you said, a pointer to a char, where you can't change the value of the char (at least not through the pointer (without casting the constness away)).
char * const的是指向一个char，在那里你可以改变字符，但你不能使指针指向一个不同的字符。
char* const is a pointer to a char, where you can change the char, but you can't make the pointer point to a different char.
为const char * const的是一个常量指针，以一个恒定的字符，即可以改变既不当指针指向，也不指针对象的值。
const char* const is a constant pointer to a constant char, i.e. you can change neither where the pointer points nor the value of the pointee.
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