问题描述
我的一个任务在写我自己的Unix外壳的。要接收来自用户的输入，我使用与fgets捕捉输入作为一个字符串，但我真的不知道它是如何工作。当我运行：
One of my assignments in to write my own UNIX Shell. To receive input from the user, I am using fgets to capture the input as a string but I'm not really sure how it works. When I run:
char command[50];
fgets(command, sizeof(command), stdin);
printf("Your Command: %s", &command);
int length = strlen(command);
printf("Length of String: %d\n", length);
比方说我输入的是退出。 strlen的说，该字符串是5个字符，而不是四个。我想这样做：
Lets say my the input was "exit". strlen says that the string is 5 characters long, instead of four. I want to do this:
if( (strcmp(command, "exit")) == 0 ){
doSomething();
}
但命令是从来没有追平字符串，我希望它;它像它有一个未知字符林不知道的。它是在最后的空字符？如何更改if语句来检查补时与fgets用户输入等于退出？谢谢！
but command is never equaling the string that I want it to; its like it has an unknown character that Im not sure of. Is it the null character at the end? How do I change the if statement to check that the user input caught with fgets equals "exit"? Thanks!
推荐答案
与fgets 认为该行结束符作为一个有效的字符。这是您收到额外的字符。
fgets considers the line terminator as a valid character. That's the extra character you are receiving.
就做类似命令[strlen的（命令） - 1] ='\\ 0'; 来删除行终止符。然后，你可以自由地做你的。
Just do something like command[strlen(command) - 1] = '\0'; to remove the line terminator. Then you are free to do all your strcmp's.
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