问题描述
我在使用strncpy时遇到困难.我正在尝试将8个字符的字符串一分为二(一个子字符串中的前6个字符,然后另一个子中的其余2个字符).为了说明特殊的困难,我将代码简化为以下内容:
I'm having difficulty with strncpy. I'm trying to split a string of 8 characters in two (the first 6 characters in one substring and then the remaining 2 characters in another). To illustrate the particular difficulty I have simplified my code to the following:
include stdio.h
include stdlib.h
include string.h
define MAXSIZE 100
struct word {
char string[8];
char sub1[2];
char sub2[6];
};
typedef struct word Word;
int main(void)
{
Word* p;
p=(Word*)malloc(MAXSIZE*sizeof(Word));
if (p==NULL) {
fprintf(stderr,"not enough memory");
return 0;
}
printf("Enter an 8-character string: \n");
scanf("%s",p->string);
strncpy(p->sub2,p->string,6);
strncpy(p->sub1,p->string,2);
printf("string=%s\n",p->string);
printf("sub1=%s\n",p->sub1);
printf("sub2=%s\n",p->sub2);
free(p);
return 0;
}
提示用户输入.假设他们输入"12345678".程序的输出为:
The user is prompted for an input. Suppose they input "12345678". Then the output of the program is:
string=1234567812123456
sub1=12123456
sub2=123456
我期望的输出如下:
string=12345678
sub1=12
sub2=123456
我不明白strncpy似乎在字符串后面加上数字...显然我不太了解strncpy,但是有人可以向我解释发生了什么吗?
I don't understand how strncpy seems to be appending numbers to string... Obviously I don't understand strncpy well enough, but can anyone explain to me what's going on?
推荐答案
C字符串需要以空字符(0)终止.
C strings need to be terminated with a null character (0).
strncpy
不会为您的字符串添加空终止符.如果要使用2个字符的字符串,则需要为3个字符分配空间,并将最后一个设置为null.
strncpy
does not put a null terminator on the string for you. If you want a 2-character string, you need to allocate room for three characters, and set the final one to null.
尝试一下:
struct word {
char string[9];
char sub1[3];
char sub2[7];
};
// ...
strncpy(p->sub2,p->string,6);
p->sub2[6] = 0;
strncpy(p->sub1,p->string,2);
p->sub1[2] = 0;
// ...
请注意,如果用户输入的字符数超出了您分配的空间,那么您最终会遇到问题.
Note that if the user inputs more characters than you've allocated room for, you'll end up with problems.
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