本文介绍了将非特化模板作为模板参数传递的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我可以做类似的事情吗

template<class Key, class Data, class Compare = less<Key>, template<typename T> class Allocator<T> = allocator<T> >
    class mymap {
        typedef map<Key,Data,Compare,Allocator<pair<const Key, Data> > > storageMap;
        typedef vector<Data,Allocator<Data> > storageVector;
}

因此模板被传递给未特化的类并稍后实例化.

So template is passed to the class unspecialiazed and instantiated later.

推荐答案

是的,这是一个最小的可编译示例:

Yes, here's a minimal compileable example:

#include <map>
#include <vector>
using namespace std;

template <
    class Key,
    class Data,
    class Compare = less<Key>,
    template <typename T> class Allocator = allocator
>
class mymap
{
public:
    typedef map<Key,Data,Compare,Allocator<pair<const Key, Data> > > storageMap;
    typedef vector<Data,Allocator<Data> > storageVector;
};

int main()
{
    mymap<int,long>::storageMap m;
    mymap<int,long>::storageVector v;
    return 0;
}

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08-21 18:52