问题描述
假设我有一个类，它看起来像这样：
Suppose I have a class that looks like this:
class Derived : // some inheritance stuff here
{
}
我要检查这样的事情在我的code：
I want to check something like this in my code:
Derived is SomeType;
不过貌似是派生是变量类型Dervied运营商的需要，不是派生本身。
我不想创建派生类型的对象。结果
如何我确保衍生继承 SOMETYPE 没有实例呢？
But looks like is operator need Derived to be variable of type Dervied, not Derived itself.I don't want to create an object of type Derived.
How can I make sure Derived inherits SomeType without instantiating it?
P.S。如果有帮助，我想是什么，其中关键字做泛型。结果
修改结果
类似答案，但它检查的对象。我要检查类本身。
P.S. If it helps, I want something like what where keyword does with generics.
Similar to this answer, but it's checking an object. I want to check the class itself.
推荐答案
要检查是否有可转让性，可以使用方法：
To check for assignability, you can use the Type.IsAssignableFrom method:
typeof(SomeType).IsAssignableFrom(typeof(Derived))
如您所愿类型平等，继承的关系和接口实现，但这种将工作的不的，当你正在寻找跨明确/隐式转换运营商的转让。
This will work as you expect for type-equality, inheritance-relationships and interface-implementations but not when you are looking for 'assignability' across explicit / implicit conversion operators.
要检查是否有严格的继承，你可以使用<$c$c>Type.IsSubclassOf:
To check for strict inheritance, you can use Type.IsSubclassOf:
typeof(Derived).IsSubclassOf(typeof(SomeType))
这篇关于如何检查是否一个类继承另一个类没有实例呢？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！