问题描述
我正在尝试使用mean(A,1)来获取矩阵A的均值行，但出现错误.
I'm trying to use mean(A,1) to get the mean row of a matrix A, but am getting an error.
例如，尝试运行命令mean(eye(3), 1).
这给出了错误no method mean(Array{Float64,2},Int32).
For example, try running the command mean(eye(3), 1).
This gives the error no method mean(Array{Float64,2},Int32).
我可以找到有关mean函数的唯一文档:
http://docs.julialang.org/en/release-0.1 /stdlib/base/#statistics
The only documentation I can find for the mean function is here:
http://docs.julialang.org/en/release-0.1/stdlib/base/#statistics
mean(v[, region])
计算整个数组v的均值，或者可选地沿region中的维计算.
Compute the mean of whole array v, or optionally along the dimensions in region.
什么是region参数?
编辑:对于Julia 0.7及更高版本，请将其写为mean(v, dims=1).
EDIT: for Julia 0.7 and higher, write this as mean(v, dims=1).
推荐答案
必须与您的安装有关，mean(eye(3),1)在这里可以正常工作.
It must be something with your installation, mean(eye(3),1) works just fine here.
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