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问题描述

我有一个如下的"AuctionResults"表

I have a table "AuctionResults" like below

Auction  Action    Shares  ProfitperShare
-------------------------------------------
Round1   BUY        6      200
Round2   BUY        5      100
Round2   SELL      -2      50
Round3   SELL      -5      80

现在,我需要在以后的回合中以先到先得"的基础扣除卖出价格后,再用每次拍卖的结果与BUYS进行汇总.

Now I need to aggregate results by every auction with BUYS after netting out SELLS in subsequent rounds on a "First Come First Net basis"

因此,在第一轮中,我买了6股股票,然后在第二轮中卖出了2股,在第三轮中剩下了"4",总净利润为6 * 200-2 * 50-4 * 80 = 780

so in Round1 I bought 6 Shares and then sold 2 in Round2 and rest "4" in Round3 with a total NET profit of 6 * 200-2 * 50-4 * 80 = 780

在Round2中,我买入5股股票并在Round3中卖出"1"(因为之前的"4"属于Round1),其净利润为5 * 100-1 * 80 = 420

and in Round2 I bought 5 shares and sold "1" in Round3(because earlier "4" belonged to Round1) with a NET Profit of 5 * 100-1 * 80 = 420

...因此,结果输出应如下所示:

...so the Resulting Output should look like:

Auction   NetProfit
------------------
Round1    780
Round2    420

我们可以仅使用Oracle SQL(10g)而不使用PL-SQL来做到这一点

Can we do this using just Oracle SQL(10g) and not PL-SQL

预先感谢

推荐答案

我知道这是一个老问题,不会对原始海报有用,但我想对此稍作尝试,因为这很有趣问题.我没有对其进行足够的测试,因此我希望仍然需要对其进行纠正和调整.但是我相信这种方法是合法的.我不建议在产品中使用这样的查询,因为这样很难维护或理解(而且我不认为这确实是可扩展的).创建一些备用数据结构会更好.话虽如此,这就是我在Postgresql 9.1中运行的:

I know this is an old question and won't be of use to the original poster, but I wanted to take a stab at this because it was an interesting question. I didn't test it out enough, so I would expect this still needs to be corrected and tuned. But I believe the approach is legitimate. I would not recommend using a query like this in a product because it would be difficult to maintain or understand (and I don't believe this is really scalable). You would be much better off creating some alternate data structures. Having said that, this is what I ran in Postgresql 9.1:

    WITH x AS (
        SELECT round, action
              ,ABS(shares) AS shares
              ,profitpershare
              ,COALESCE( SUM(shares) OVER(ORDER BY round, action
                                          ROWS BETWEEN UNBOUNDED PRECEDING
                                                   AND 1 PRECEDING)
                        , 0) AS previous_net_shares
              ,COALESCE( ABS( SUM(CASE WHEN action = 'SELL' THEN shares ELSE 0 END)
                            OVER(ORDER BY round, action
                                     ROWS BETWEEN UNBOUNDED PRECEDING
                                              AND 1 PRECEDING) ), 0 ) AS previous_sells
          FROM AuctionResults
          ORDER BY 1,2
    )

    SELECT round, shares * profitpershare - deduction AS net
      FROM (

           SELECT buy.round, buy.shares, buy.profitpershare
                 ,SUM( LEAST( LEAST( sell.shares, GREATEST(buy.shares - (sell.previous_sells - buy.previous_sells), 0)
                                    ,GREATEST(sell.shares + (sell.previous_sells - buy.previous_sells) - buy.previous_net_shares, 0)
                                   )
                             ) * sell.profitpershare ) AS deduction
             FROM x buy
                 ,x sell
             WHERE sell.round > buy.round
               AND buy.action = 'BUY'
               AND sell.action = 'SELL'
             GROUP BY buy.round, buy.shares, buy.profitpershare

           ) AS y

结果:

     round | net
    -------+-----
         1 | 780
         2 | 420
    (2 rows)

为了将其分解成几部分,我从以下数据集开始:

To break it down into pieces, I started with this data set:

    CREATE TABLE AuctionResults( round int, action varchar(4), shares int, profitpershare int);

    INSERT INTO AuctionResults VALUES(1, 'BUY', 6, 200);
    INSERT INTO AuctionResults VALUES(2, 'BUY', 5, 100);
    INSERT INTO AuctionResults VALUES(2, 'SELL',-2, 50);
    INSERT INTO AuctionResults VALUES(3, 'SELL',-5, 80);
    INSERT INTO AuctionResults VALUES(4, 'SELL', -4, 150);

    select * from auctionresults;

     round | action | shares | profitpershare
    -------+--------+--------+----------------
         1 | BUY    |      6 |            200
         2 | BUY    |      5 |            100
         2 | SELL   |     -2 |             50
         3 | SELL   |     -5 |             80
         4 | SELL   |     -4 |            150
    (5 rows)

"WITH"子句中的查询将一些运行总计添加到表中.

The query in the "WITH" clause adds some running totals to the table.

  • "previous_net_shares"指示在当前记录之前可以出售多少股票.这也告诉我在开始将其分配给此购买"之前,需要跳过多少卖出"份额.
  • "previous_sells"是所遇到的卖出"份额数量的连续计数,因此,两个"previous_sells"之间的差表示该时间使用的卖出"份额数量.

  • "previous_net_shares" indicates how many shares are available to sell before the current record. This also tells me how many 'SELL' shares I need to skip before I can start allocating it to this 'BUY'.
  • "previous_sells" is a running count of the number of "SELL" shares encountered, so the difference between two "previous_sells" indicates the number of 'SELL' shares used in that time.

 round | action | shares | profitpershare | previous_net_shares | previous_sells
-------+--------+--------+----------------+---------------------+----------------
     1 | BUY    |      6 |            200 |                   0 |              0
     2 | BUY    |      5 |            100 |                   6 |              0
     2 | SELL   |      2 |             50 |                  11 |              0
     3 | SELL   |      5 |             80 |                   9 |              2
     4 | SELL   |      4 |            150 |                   4 |              7
(5 rows)

使用此表,我们可以进行自连接,其中每个购买"记录都与每个将来的出售"记录相关联.结果将如下所示:

With this table, we can do a self-join where each "BUY" record is associated with each future "SELL" record. The result would look like this:

    SELECT buy.round, buy.shares, buy.profitpershare
          ,sell.round AS sellRound, sell.shares AS sellShares, sell.profitpershare AS sellProfitpershare
      FROM x buy
          ,x sell
      WHERE sell.round > buy.round
        AND buy.action = 'BUY'
        AND sell.action = 'SELL'

     round | shares | profitpershare | sellround | sellshares | sellprofitpershare
    -------+--------+----------------+-----------+------------+--------------------
         1 |      6 |            200 |         2 |          2 |                 50
         1 |      6 |            200 |         3 |          5 |                 80
         1 |      6 |            200 |         4 |          4 |                150
         2 |      5 |            100 |         3 |          5 |                 80
         2 |      5 |            100 |         4 |          4 |                150
    (5 rows)

然后出现了一个疯狂的部分,它试图计算订单中可供出售的股票数量与尚未购买的总股数.这里有一些注意事项,以帮助您遵循.带"0"的最大"调用仅表示如果我们为负数,则无法分配任何份额.

And then comes the crazy part that tries to calculate the number of shares available to sell in the order vs the number over share not yet sold yet for a buy. Here are some notes to help follow that. The "greatest"calls with "0" are just saying we can't allocate any shares if we are in the negative.

   -- allocated sells
   sell.previous_sells - buy.previous_sells

   -- shares yet to sell for this buy, if < 0 then 0
   GREATEST(buy.shares - (sell.previous_sells - buy.previous_sells), 0)

   -- number of sell shares that need to be skipped
   buy.previous_net_shares

感谢David的协助

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08-21 15:03